The equatorial aspect of the Peirce quincuncial projection, which is available in d3-geo-projection. By setting the clip angle to 90°, you can produce the Adams hemisphere-in-a-square projection.
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July 25, 2019 21:23
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Peirce Equatorial
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license: gpl-3.0 | |
height: 960 | |
border: no | |
redirect: https://observablehq.com/@d3/peirce-quincuncial |
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<!DOCTYPE html> | |
<meta charset="utf-8"> | |
<style> | |
.graticule { | |
fill: none; | |
stroke: #777; | |
stroke-width: 0.5px; | |
stroke-opacity: 0.5; | |
} | |
.land { | |
fill: #222; | |
} | |
.boundary { | |
fill: none; | |
stroke: #fff; | |
stroke-width: 0.5px; | |
} | |
</style> | |
<svg width="960" height="960"></svg> | |
<script src="//d3js.org/d3.v4.min.js"></script> | |
<script src="//d3js.org/d3-geo-projection.v1.min.js"></script> | |
<script src="//d3js.org/topojson.v1.min.js"></script> | |
<script> | |
var svg = d3.select("svg"), | |
width = +svg.attr("width"), | |
height = +svg.attr("height"), | |
g = svg.append("g").attr("transform", "rotate(90 480,480)"); | |
var projection = d3.geoPierceQuincuncial() // N.B. geoPeirceQuincuncial in 1.1+ | |
.scale(214) | |
.translate([width / 2, height / 2]) | |
.rotate([0, 0, 45]) | |
.precision(0.1); | |
var path = d3.geoPath() | |
.projection(projection); | |
var graticule = d3.geoGraticule(); | |
g.append("path") | |
.datum(graticule) | |
.attr("class", "graticule") | |
.attr("d", path); | |
g.append("path") | |
.datum({type: "Sphere"}) | |
.attr("class", "sphere") | |
.attr("d", path) | |
.attr("fill", "none") | |
.attr("stroke", "black"); | |
d3.json("/mbostock/raw/4090846/world-50m.json", function(error, world) { | |
if (error) throw error; | |
g.insert("path", ".graticule") | |
.datum(topojson.feature(world, world.objects.land)) | |
.attr("class", "land") | |
.attr("d", path); | |
g.insert("path", ".graticule") | |
.datum(topojson.mesh(world, world.objects.countries, function(a, b) { return a !== b; })) | |
.attr("class", "boundary") | |
.attr("d", path); | |
}); | |
</script> |
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