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February 19, 2018 16:29
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1,2,3,4,5,6,7,8,9の間に+,-,xのうちどれかを入れて結果が1となるようなものを抽出
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for i in range(6561): #6561=3^8 | |
numli = [1,2,3,4,5,6,7,8,9] #計算式に出てくる数字 | |
calcli = [] #+を0,-を1,xを2として3進法8桁で演算子を表す | |
while i != 0: | |
calcli.append(int(i%3)) | |
i = int(i/3) | |
if(len(calcli)<8): #8桁に足りない部分は全部0にする | |
for j in range(8-len(calcli)): | |
calcli.append(0) | |
calcli.reverse() #全通り試すのでなくてもいい | |
calcli_dumy = [] #calcliをコピー | |
for j in range(len(calcli)): | |
calcli_dumy.append(calcli[j]) | |
#乗算は先に処理 | |
for j in range(8): | |
if calcli[j] == 2: | |
numli[j+1] *= numli[j] | |
numli[j] = -1 #乗算をした数字は使わない | |
calcli[j] = -1 #乗算をした演算子は使わない | |
while -1 in numli: | |
numli.remove(-1) | |
calcli.remove(-1) | |
result = numli[0] | |
#以下加算と減算 | |
for j in range(len(calcli)): | |
if calcli[j] == 0: | |
result += numli[j+1] | |
elif calcli[j] == 1: | |
result -= numli[j+1] | |
#結果が1なら合致なのでその計算を文字列で取り出す | |
if result == 1: | |
string = "1" | |
for j in range(8): | |
if calcli_dumy[j]==0: | |
string += "+" + str(j+2) | |
elif calcli_dumy[j]==1: | |
string += "-" + str(j+2) | |
elif calcli_dumy[j]==2: | |
string += "x" + str(j+2) | |
string += "=1" | |
print(string) |
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