# aemkei / LICENSE.txt Created August 22, 2011 — forked from 140bytes/LICENSE.txt

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Latitude Longitude Distance - 140byt.es

 1 2 3 4 5 6 7 8 9 10 11 12 13 ``` DO WHAT THE FUCK YOU WANT TO PUBLIC LICENSE Version 2, December 2004   Copyright (C) 2011 YOUR_NAME_HERE   Everyone is permitted to copy and distribute verbatim or modified copies of this license document, and changing it is allowed as long as the name is changed.   DO WHAT THE FUCK YOU WANT TO PUBLIC LICENSE TERMS AND CONDITIONS FOR COPYING, DISTRIBUTION AND MODIFICATION   0. You just DO WHAT THE FUCK YOU WANT TO. ```

# Game of Life - 140byt.es

This uses the Haversine formula to calculate the great-circle distance between two points.

## Usage

```distanceLatLng (
latitude1, longitude1 // first coordinates
latitude2, longitude2 // seconds coordinates
diameter // earth diameter (might be any unit)
)

// returns the distance in the specified unit```

### Earth Diameter

• 2 * 6378.137 Kilometers
• 2 * 6378137 Meter
• 2 * 3963.190 Miles

## Author

Created by Martin Kleppe (@aemkei) at Ubilabs.

See the 140byt.es site for a showcase of entries (built itself using 140-byte entries!), and follow @140bytes on Twitter.

 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 ```function( a, b, // first coord c, d, // second coord e, // earth diameter (might be any unit) z, i // placeholder ){ with (Math) { // use "Math" in context z = PI / 360; // used to convert in radiants return e * atan2( sqrt( i = pow(sin((c-a)*z), 2) + cos(a*z*2) * cos(c*z*2) * pow(sin((d-b)*z), 2) ), sqrt(1-i) ); } } ```
 1 2 3 4 5 6 7 8 9 10 11 ```{ "name": "distanceLatLng",   "description": "Calculate distance between Latitude/Longitude points.",   "keywords": [ "geo", "maps", "distance" ] } ```
 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 ``` Distance between Latitude/Longitude points

Distance Hamburg-Tokyo

8986 km expected
km calculated
5584 miles expected
miles calculated
```

Great job! Flawless stereometry packed into tweet.

The only one suggestion, as the assignment has very low precedence we may re-use `z` variable instead of `i`

`function(a,b,c,d,e,z){with(Math)return z=PI/360,e*atan2(sqrt(z=pow(sin((c-a)*z),2)+cos(a*z*2)*cos(c*z*2)*pow(sin((d-b)*z),2)),sqrt(1-z))}`
Owner

Thanks for that suggestion. It saved another 2 bytes!