Created
February 11, 2020 13:24
-
-
Save 1604078-MEHEDI/aec3f6608e302548687b8c25939c097a to your computer and use it in GitHub Desktop.
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
///https://www.spoj.com/problems/KATHTHI/ | |
// Topic: 0-1 bfs | |
#include <bits/stdc++.h> | |
using namespace std; | |
#define INF 1<<30 | |
#define endl '\n' | |
#define maxn 1000005 | |
#define FASTIO ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0); | |
typedef long long ll; | |
const double PI = acos(-1.0); | |
const ll mod = 1e9 + 7; | |
inline void normal(ll &a) { a %= mod; (a < 0) && (a += mod); } | |
inline ll modMul(ll a, ll b) { a %= mod, b %= mod; normal(a), normal(b); return (a * b) % mod; } | |
inline ll modAdd(ll a, ll b) { a %= mod, b %= mod; normal(a), normal(b); return (a + b) % mod; } | |
inline ll modSub(ll a, ll b) { a %= mod, b %= mod; normal(a), normal(b); a -= b; normal(a); return a; } | |
inline ll modPow(ll b, ll p) { ll r = 1; while (p) { if (p & 1) r = modMul(r, b); b = modMul(b, b); p >>= 1; } return r; } | |
inline ll modInverse(ll a) { return modPow(a, mod - 2); } | |
inline ll modDiv(ll a, ll b) { return modMul(a, modInverse(b)); } | |
///** | |
template < typename F, typename S > | |
ostream& operator << ( ostream& os, const pair< F, S > & p ) { | |
return os << "(" << p.first << ", " << p.second << ")"; | |
} | |
template < typename T > | |
ostream &operator << ( ostream & os, const vector< T > &v ) { | |
os << "{"; | |
for (auto it = v.begin(); it != v.end(); ++it) { | |
if ( it != v.begin() ) os << ", "; | |
os << *it; | |
} | |
return os << "}"; | |
} | |
template < typename T > | |
ostream &operator << ( ostream & os, const set< T > &v ) { | |
os << "["; | |
for (auto it = v.begin(); it != v.end(); ++it) { | |
if ( it != v.begin()) os << ", "; | |
os << *it; | |
} | |
return os << "]"; | |
} | |
template < typename F, typename S > | |
ostream &operator << ( ostream & os, const map< F, S > &v ) { | |
os << "["; | |
for (auto it = v.begin(); it != v.end(); ++it) { | |
if ( it != v.begin() ) os << ", "; | |
os << it -> first << " = " << it -> second ; | |
} | |
return os << "]"; | |
} | |
#define dbg(args...) do {cerr << #args << " : "; faltu(args); } while(0) | |
clock_t tStart = clock(); | |
#define timeStamp dbg("Execution Time: ", (double)(clock() - tStart)/CLOCKS_PER_SEC) | |
void faltu () { cerr << endl; } | |
template <typename T> | |
void faltu( T a[], int n ) { | |
for (int i = 0; i < n; ++i) cerr << a[i] << ' '; | |
cerr << endl; | |
} | |
template <typename T, typename ... hello> | |
void faltu( T arg, const hello &... rest) { cerr << arg << ' '; faltu(rest...); } | |
// Program showing a policy-based data structure. | |
#include <ext/pb_ds/assoc_container.hpp> // Common file | |
#include <ext/pb_ds/tree_policy.hpp> | |
#include <functional> // for less | |
#include <iostream> | |
using namespace __gnu_pbds; | |
using namespace std; | |
// GNU link : https://goo.gl/WVDL6g | |
typedef tree<int, null_type, less_equal<int>, rb_tree_tag, | |
tree_order_statistics_node_update> | |
new_data_set; | |
// find_by_order(k) – ফাংশনটি kth ordered element এর একটা পয়েন্টার রিটার্ন করে। অর্থাৎ তুমি চাইলেই kth ইন্ডেক্সে কি আছে, সেটা জেনে ফেলতে পারছো! | |
// order_of_key(x) – ফাংশনটি x এলিমেন্টটা কোন পজিশনে আছে সেটা বলে দেয়। | |
//*//**___________________________________________________**/ | |
bool is_valid(int a, int b, int c, int d) | |
{ | |
return (a >= 0 && a < c && b >= 0 && b < d); | |
} | |
int main() | |
{ | |
FASTIO | |
///* | |
#ifndef ONLINE_JUDGE | |
freopen("in.txt", "r", stdin); | |
freopen("out.txt", "w", stdout); | |
freopen("error.txt", "w", stderr); | |
#endif | |
//*/ | |
int T; | |
//scanf("%d", &T); | |
T = 1; | |
cin >> T; | |
for (int cs = 1; cs <= T; cs++) { | |
int n, m; | |
cin >> n >> m; | |
vector<string> str(n); | |
for (int i = 0; i < n; i++) cin >> str[i]; | |
int vis[n][m]; | |
for (int i = 0; i < n; i++) | |
for (int j = 0; j < m; j++) vis[i][j] = INT_MAX; | |
deque<pair<int, int>> dQ; | |
vis[0][0] = 1; | |
dQ.push_front({0, 0}); | |
int dx[] = {1, -1, 0, 0}; | |
int dy[] = {0, 0, 1, -1}; | |
while (!dQ.empty()) { | |
auto it = dQ.front(); | |
dQ.pop_front(); | |
int x = it.first; | |
int y = it.second; | |
if (x == n - 1 && y == m - 1) break; | |
for (int i = 0; i < 4; i++) { | |
int r = it.first + dx[i]; | |
int c = it.second + dy[i]; | |
if (is_valid(r, c, n, m)) { | |
if (str[r][c] == str[x][y] && vis[r][c] > vis[x][y]) { | |
vis[r][c] = vis[x][y]; | |
dQ.push_front({r, c}); | |
} | |
else if ( vis[r][c] > vis[x][y] + 1) { | |
vis[r][c] = vis[x][y] + 1; | |
dQ.push_back({r, c}); | |
} | |
} | |
} | |
} | |
cout << vis[n - 1][m - 1] - 1 << endl; | |
} | |
return 0; | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment