Fizzbuzz via answers.com

fizzbuzz.py

''' we're solving fizzbuzz with a little help from the web '''
from html.parser import HTMLParser
from urllib.request import Request, urlopen
import re
import time

base_url = 'https://www.answers.com/Q/'
tag_name = 'div'
class_name = 'answer-body'
delimiter = '_'

class SearchParser(HTMLParser):
    ''' Parses search results from the web '''
    def __init__(self):
        HTMLParser.__init__(self)
        # track if the data we're encountering is part of an answer. we have
        # to do this because there can be nested tags inside the answer tag
        self.in_answer = False

        # keep track of nested tags
        self.tag_stack = []

        # a list of all the answers found
        self.answers = []

        # words that indicate whether the answer is yes or no
        self.positive_signs = [
            'yes',
            'exactly',
            'is divisible',
        ]
        self.negative_signs = [
            'no',
            'not',
            'decimal',
        ]

    def handle_starttag(self, tag, attrs):
        ''' identify the tag that we expect to contain the answer '''
        if tag == tag_name:
            for attr in attrs:
                if attr[0] == 'class' and class_name in attr[1]:
                    self.in_answer = True
                    self.answers.append('')
                    break

        if self.in_answer:
            self.tag_stack.append(tag)

    def handle_endtag(self, tag):
        ''' behavior on encountering a close tag '''
        self.tag_stack = self.tag_stack[:-1]
        # if the stack is empty, we're done with that answer
        if self.in_answer and self.tag_stack == []:
            self.in_answer = False

    def handle_data(self, data):
        ''' extract the answer, if we're in an answer tag '''
        if self.in_answer:
            self.answers[-1] += data

    def conclude_yes_no(self):
        ''' looks through all the answer to conclude either true or false '''
        results = 0
        for answer in self.answers:
            answer = answer.lower().strip()
            results += self.score_answer(answer)
        return results > 0

    def score_answer(self, answer):
        ''' evaluates an answer to determine if it's a yes or a no '''
        score = 0
        positive_signs = re.findall(
            r'\b%s\b' % r'\b|\b'.join(self.positive_signs),
            answer,
        )
        score += len(positive_signs)
        negative_signs = re.findall(
            r'\b%s\b' % r'\b|\b'.join(self.negative_signs),
            answer
        )
        score -= len(negative_signs)
        return score

def query_search_engine(numerator, denominator):
    ''' ask a search engine if these numbers are divisible '''
    question = 'is %d divisible by %d' % (numerator, denominator)
    question = question.replace(' ', delimiter)
    url = '%s%s' % (base_url, question)
    request = Request(url)
    request.add_header(
        'User-Agent',
        'Mozilla/5.0 (Macintosh; Intel Mac OS X 10.15; rv:72.0) ' \
                'Gecko/20100101 Firefox/72.0')
    response = urlopen(request)
    # politeness -- wait a few seconds before the next query
    time.sleep(3)
    if url != response.url:
        return False
    text = response.read().decode('unicode-escape')
    parser = SearchParser()
    parser.feed(text)
    return parser.conclude_yes_no()


if __name__ == '__main__':
    divisors = [(3, 'fizz'), (5, 'buzz')]
    for i in range(1, 101):
        output = ''
        for d in divisors:
            if query_search_engine(i, d[0]):
                output += d[1]
        output = output or i
        print(output)

# cool

This solution blows my mind.

New Era of cloud computing

Salient and timely.

Waiitt a minute.... ._.

Waiitt a minute.... ._.

https://www.answers.com/Q/is_17_divisible_by_3

answers.com wouldn't lead us astray.

Wow. My world has changed

"There are four lights!" -Jean-Luc Picard
Star Trek The Next Generation, Season 10 Episodes 10 and 11: Chain of Command
https://en.wikipedia.org/wiki/Chain_of_Command_(Star_Trek:_The_Next_Generation)