Test of regexp

regexp_phone_number2.py

#This script creates dictionary, where we have mobile operator and mobile code 

import re

#country_code_ukraine = '+380'
string_may_be = '38066-44-89-555aaa'


def parse_phone_for_provider(string_may_be):

    final_result = dict(carier='', code='', number='')

    if (string_may_be is None):
        print ('There is no value in input variavle. Exception') 
    else:
        print 'We will check it ',string_may_be
        #1. Clean all symbols except numbers
        print '\n String with only digits: '
 
        clean_string = re.sub('\D','',string_may_be)
        print clean_string
        
        #2. Create dictionary of known mobile providers (from Wiki)
        
        mob = dict() 
        mob['50']='Vodafone'
        mob['95']='Vodafone'
        mob['66']='Vodafone'
        mob['99']='Vodafone'
        mob['63']='lifecell'                
        mob['73']='lifecell'
        mob['93']='lifecell'
        mob['68']='Kyivstar'  
        mob['67']='Kyivstar'  
        mob['96']='Kyivstar'
        mob['97']='Kyivstar'
        mob['98']='Kyivstar'
        mob['91']='3mob (Ukraine)'
        mob['92']='PEOPLEnet'
        mob['68']='Intertelecom'

        # 2a
        if len(clean_string) == 12: #[380-67-1234567] Something+2+7
            result = re.match(r'(?P<code>\d{3})(?P<carier>\d{2})(?P<number>\d{7})', clean_string)         
        elif len(clean_string) == 11: #[80-67-1234567] Something+2+7
            result = re.match(r'(?P<code>\d{2})(?P<carier>\d{2})(?P<number>\d{7})', clean_string)
        elif len(clean_string) == 10: #[0-67-1234567] Something+2+7
            result = re.match(r'(?P<code>\d{1})(?P<carier>\d{2})(?P<number>\d{7})', clean_string)     
        else:
            return False      
            
        final_result = result.groupdict()
        final_result['carier'] = mob.get(final_result['carier'])    
                       
        #3. Return
    return final_result;

if __name__ == '__main__':
    print parse_phone_for_provider(string_may_be)