Counting number of elements in a list that meet criteria

gistfile1.txt

from timeit import Timer

if __name__ == "__main__":
    setup = 'x = list(range(100000))'
    num_iter = 1000
    print(Timer('sum(1 for item in x if item % 2 == 0)', setup).timeit(num_iter))
    print(Timer('len([item for item in x if item % 2 == 0])', setup).timeit(num_iter))

# prints (on my machine):
# 12.4215...
# 10.9932...
# showing that the len() on a list comp is a bit faster.