[python] start debugger on exception

sitecustomize.py

#
# original: http://code.activestate.com/recipes/65287/
#

# place in lib/python2.x/sitecustomize.py
import bdb
import sys

def info(type, value, tb):
   if hasattr(sys, 'ps1') \
         or not sys.stdin.isatty() \
         or not sys.stdout.isatty() \
         or not sys.stderr.isatty() \
         or issubclass(type, bdb.BdbQuit) \
         or issubclass(type, SyntaxError):
      # we are in interactive mode or we don't have a tty-like
      # device, so we call the default hook
      sys.__excepthook__(type, value, tb)
   else:
      import traceback, pdb
      # we are NOT in interactive mode, print the exception...
      traceback.print_exception(type, value, tb)
      print
      # ...then start the debugger in post-mortem mode.
      pdb.pm()

sys.excepthook = info

great. I am looking a way to implement this as a python argument. for example:
python -pm script.py
Any idea?

I test for an environment variable, which means I can just use:

AUTOPDB=true python script.py

Not quite an argument, but easy to do on a once-off basis (or, indeed, set for a shell session).

Or, you could put it into a module called 'pm.py' in your path, and do it as:

python -mpm script.py