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Activity Selection Problem - solution accepted GeekforGeeks
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/** | |
Activity Selection Problem | |
https://en.wikipedia.org/wiki/Activity_selection_problem | |
*/ | |
#include <stdio.h> | |
#define FIN "activity2.in" | |
#define FOUT "activity.out" | |
#define SIZE 100 | |
typedef struct activity { | |
int start, | |
end, | |
key; | |
} activity; | |
activity spectacle[ SIZE ]; | |
int number_of_spectacles; | |
int sol[SIZE], | |
countSol; | |
void sort(); | |
void greedy(); | |
int main() { | |
int T, it; | |
scanf("%d", &T); | |
while(T--) { | |
scanf("%d", &number_of_spectacles); | |
for(it = 1; it <= number_of_spectacles; it++) | |
scanf("%d",&spectacle[it].start); | |
for(it = 1; it <= number_of_spectacles; it++) | |
scanf("%d",&spectacle[it].end); | |
sort(); | |
greedy(); | |
printf("%d\n", countSol); | |
} | |
}; | |
void sort() { | |
activity temp; | |
int i, swapped = 1; | |
while(swapped) { | |
swapped = 0; | |
for(i = 1; i < number_of_spectacles; i++) { | |
if(spectacle[i].end > spectacle[i+1].end) { | |
temp = spectacle[i]; | |
spectacle[i] = spectacle[i+1]; | |
spectacle[i+1] = temp; | |
swapped = 1; | |
} | |
} | |
} | |
}; | |
void greedy() { | |
int i, j = 1; | |
sol[ j ] = 1; | |
for(i = 2; i <= number_of_spectacles;i++) { | |
if(spectacle[i].start >= spectacle[sol[j]].end) { | |
sol[++j] = i; | |
} | |
countSol = j; | |
} | |
}; |
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