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Areahints / bars.geojson
Created Jul 15, 2019
A collaborative list of DC locations that serve up both Internet and Alcohol - last updated 2015 (original project here - )
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Areahints /
Last active Jul 15, 2019
This gist is a showcase for readers of

What expression does this meow to?

Areahints /
Last active Jun 14, 2019
[Algorithm question by Google] solve for O(nlogn) #python3 #big-o


We can determine how "out of order" an array A is by counting the number of inversions it has.

Two elements A[i] and A[j] form an inversion if A[i] > A[j] but i < j. That is, a smaller element appears after a larger element.


Given an array, count the number of inversions it has. Do this faster than O(N2) time.

Areahints /
Last active Jun 1, 2019
[Hackerrank Interview Preparation Kit] Warm-up Challenges

Gary is an avid hiker. He tracks his hikes meticulously, paying close attention to small details like topography. During his last hike he took exactly n steps. For every step he took, he noted if it was an uphill, U, or a downhill, D step. Gary's hikes start and end at sea level and each step up or down represents a unit change in altitude. We define the following terms:

A mountain is a sequence of consecutive steps above sea level, starting with a step up from sea level and ending with a step down to sea level. A valley is a sequence of consecutive steps below sea level, starting with a step down from sea level and ending with a step up to sea level. Given Gary's sequence of up and down steps during his last hike, find and print the number of valleys he walked through.

For example, if Gary's path is s =[DDUUUUDD], he first enters a valley 2 units deep. Then he climbs out an up onto a mountain 2 units high. Finally, he returns to sea level and ends his hike.

Function Description


Complete the function solveMeFirst to compute the sum of two integers.

Function prototype:

int solveMeFirst(int a, int b);


  • a is the first integer input.
Areahints /
Last active May 30, 2019
Andela Home study

Compares the two trees defined by Nodes a and b and returns true if they are equal in structure and in value

def compare(a, b):
    if a == b:
        return True
    if a is None or b is None:
        return False
    if a.val != b.val:
        return False
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