Reverse a linked list.
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#include <iostream> | |
#include <vector> | |
class Node { | |
public: | |
int data; | |
Node* next; | |
Node(int data) { | |
this->data = data; | |
next = NULL; | |
} | |
}; | |
void reverseLinkedListV1(Node*& head) { | |
Node* temp = head; | |
std::vector<Node*> addresses; | |
do { | |
addresses.push_back(&(*temp)); | |
} while ((temp = temp->next) != NULL); | |
head = temp = *(&addresses[addresses.size() - 1]); | |
for (int i = addresses.size() - 2; i >= 0; i--) | |
temp = temp->next = *(&addresses[i]); | |
temp->next = NULL; | |
} | |
void printLinkedList(Node* head) { | |
if (head == NULL) | |
return; | |
Node* temp = head; | |
do { | |
std::cout << temp->data << " ";//std::endl; | |
// temp = temp->next; | |
} while ((temp = temp->next) != NULL); | |
std::cout << std::endl; | |
} | |
int main(int argc, char const* argv[]) | |
{ | |
Node* list; | |
list = new Node(0); | |
list->next = new Node(1); | |
list->next->next = new Node(2); | |
list->next->next->next = new Node(3); | |
list->next->next->next->next = new Node(4); | |
list->next->next->next->next->next = new Node(5); | |
list->next->next->next->next->next->next = new Node(6); | |
list->next->next->next->next->next->next->next = new Node(7); | |
list->next->next->next->next->next->next->next->next = new Node(8); | |
list->next->next->next->next->next->next->next->next->next = new Node(9); | |
printLinkedList(list); | |
reverseLinkedListV1(list); | |
printLinkedList(list); | |
return 0; | |
} |
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