Flatten a Dictionary - https://www.pramp.com/challenge/AMypWAprdmUlaP2gPVLZ

FlattenDictionary.py

def flatten_dictionary(dictionary):
  
  flattened = {}
  flattened = flatten_helper("", dictionary, flattened)
  return flattened
  
  def flatten_helper(initKey, dictionary, flattened):
    for k, v in dictionary:
      if not isInstance(v, dict):
        if initKey is None or initKey == "":
          flattened[k] = v
          return flattened
        else:
          flattened[initKey + "." + k] = v
          return flattened
      else:
        if initKey is None or initKey == "":
          flatten_helper(k, v, flattened)
        else:
          flatten_helper(initKey + "." + k, v, flattened)




"""
cant hear u can u refresh

time: 
meaning?? 

key1 1 <-

nested(dictlistkey):
  if len(keys[values]) > 1



def flatten(dictList, KVList, index=1):

  if index = len(dictList):
    return KVList
    
  if nested(dictListkey) is False:
    newKV = (key: value) 
    KVList.append(newKV) 
  
  else:
    dictListindex = dictListindex+1[key]  + dictList+1[value]
    flatten(dictList, KVList, prev_key + "." + current_key)
  

return



{
            "Key1" : "1", < - base 
            "Key2" : {   <- recursive
                "a" : "2"
             }
}   


key2 
  a: 2
  b: 3
    c:
      d: 3
      e: 
       "" : 1

output: {
            "Key1" : "1", <-
            "Key2.a" : "2",
            "Key2.b" : "3",
            "Key2.c.d" : "3",
            "Key2.c.e" : "1"
        }

          
             
                

"""