x^y=y^xの組み合わせを見つける

2442.js

// RunProcess(最小指数, 最大指数, 底)
function RunProcess(startNum, processMax, ProcX){

    for (let i = BigInt(startNum); i <= processMax; i++) {

        let AnswerA, AnswerB
        ProcX=BigInt(ProcX)

        // ProcY=BigInt(processMax)-BigInt(i)
        ProcY=BigInt(i)
        console.log(`検証: ${ProcX} ** ${ProcY}`)
        
        if (ProcX === ProcY ){
            continue;
        }

        AnswerA = ProcX ** ProcY
        AnswerB = ProcY ** ProcX
        if (AnswerA === AnswerB){
            console.log(`結果: ${ProcX} ^ ${ProcY} == ${AnswerA}`)
        }
    }
}

const AllMax = 1000n


for (let x = BigInt(0); x <= AllMax; x++) {
    RunProcess(0,AllMax, x)
}