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A simple C program to decompose a number in powers of 10
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#include <stdio.h> | |
#include <stdlib.h> | |
#include <math.h> | |
#include <inttypes.h> | |
#define POWER(x, y) (long int)pow(x, (float)y) | |
uint8_t* puzzledNumber(int32_t number, uint16_t *size) | |
{ | |
int16_t i = 0, j = 0, k = 0; | |
while(POWER(10, *size) <= number) | |
{ | |
(*size)++; | |
} | |
uint8_t *tab = calloc(sizeof(*tab), *size); | |
for(i = 0; i < *size; i++) | |
{ | |
tab[i] = number / POWER(10, *size - i - 1); | |
for(j = i - 1, k = 1; j >= 0; j--, k++) | |
{ | |
tab[i] -= tab[j] * POWER(10, k); | |
} | |
} | |
return tab; | |
} | |
int main(int argc, char const *argv[]) | |
{ | |
(void)argc; | |
(void)argv; | |
int32_t number = 0; | |
scanf("%d", &number); | |
uint16_t size = 0; | |
uint8_t *tab = puzzledNumber(number, &size); | |
if(tab != NULL) | |
{ | |
for(uint16_t i = 0; i < size; i++) | |
{ | |
printf("%d ", tab[i]); | |
} | |
printf("\n"); | |
free(tab); | |
tab = NULL; | |
} | |
return 0; | |
} |
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