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Spelling Bee
main.prof
main
*.txt

Spelling Bee

Generates NYT Spelling Bee puzzles and answers

Rules

Spelling Bee puzzles present solvers with seven letters in a circle, with one letter in the middle. The game is to identify as many words as possible using only these letters, which can be repeated, and where the letter in the center must be used.

Each word is worth one point, and words using all seven letters are worth three points.

Generally, underneath the puzzle there's a scale saying "XX points is good, YY points is great, ZZ points is genius". The list of answers is printed in next week's issue.

Example

For the purposes of generating puzzles, a puzzle is considered "valid" if it has at least ten answers, to weed out puzzles with too few answers, and if there is at least one answer that uses every letter, because finding the three-pointer is best part.

Runtime

Without parallelism, generating seven-letter puzzles takes about five and a half hours, and generates 51,912 unique puzzles.

Results

The list of all valid puzzles is here: https://storage.googleapis.com/spelling-bee/ls-7.txt

The name of the puzzle is the letters in the puzzle, sorted A-Z, then rotated so that the required letter is first.

A puzzle with letters R, T, D, A, S, I, and the required center letter E is named by the letters in the puzzle, sorted (adeirst), then rotated so it starts with e (eirstad).

So the answers to that puzzle are at: https://storage.googleapis.com/spelling-bee/eirstad.txt

The last line of the file is the total number of points for that puzzle.

Findings

Longest answers

48 puzzles include an answer with 15 letters, all of which are three-point answers.

unconsciousness
superstructures
nonintervention
interconnection
inconveniencing
inconsistencies
consciousnesses
nationalization

Most popular answers

The most popular answer is "deeded", which is found in 3,630 different puzzles. Basically, any puzzle that has "e" and "d" in it, where either "e" or "d" is the required letter.

3630 deeded
3569 sissies
3569 sises
3516 serer
3516 seers
 ...

Least popular answers

62 different words are only found once in all the puzzles.

Nearly all of these are three-point answers using all the letters in the puzzle. Exceptions come from puzzles without enough answers to be valid, or answers like chintz where the only longer answer is chintzy which is a three-point answer.

backward
bigotry
blindfold
bloodhound
bobwhite
bullhorn
bumpkin
burdock
chintz
chintzy
crudity
dizzy
dogfight
drawback
equinox
exorcize
forklift
fortify
frigidity
fullback
girlhood
gluttony
gryphon
halfback
helpful
homepage
homophobia
hoodwink
horribly
hunchback
hurtful
imbroglio
invincibly
jackpot
jollity
jovial
jovially
judicial
kazoo
liturgy
luxury
menfolk
mindful
monthly
mortify
mythology
orthodoxy
pettifog
prodigy
public
publicly
quandary
quickly
rhombi
rhomboid
truthful
truthfully
unkempt
unmindful
wakeful
windfall
withhold

Puzzles with the most answers

The puzzle eirstad has the most answers, at 456. Interestingly, deeded is an answer in the #1 and #3 puzzles in the list.

456 eirstad
445 eiprsta
440 eprstad
440 einrsta
439 elprsta
...

Puzzles worth the most total points:

The puzzle einrsta (#4 on the list of most answers) has the most total points available, because it contains a lot 3-point answers.

The puzzle with the most answers, eirstad, has the second-most available points.

504 einrsta
484 eirstad
484 staeinr
484 taeinrs
482 einrstd
...

Puzzles with the fewest answers

There are 563 puzzles with only ten answers, among them:

abcdkrw
abcfhkl
abdgotu
abehitu
abeiotv
...and 558 more

Puzzles worth the fewest total points:

517 puzzles only have 12 points.

12 points is the fewest possible points for a valid puzzle, since every puzzle must have ten answers and at least one of them must be worth three points.

abcfhkl
abdgotu
abehitu
abeiotv
aceiloz
...and 512 more

Puzzles that have only 10 answers worth more than 12 points must include multiple three-point answers.

Other puzzle variants

Nothing requires the puzzle to have 7 available letters. If we only provide 6 letters, we get fewer valid puzzles, but it takes less time to compute them.

# letters time # puzzles
3 20s 0
4 2m20s 189
5 10m29s 6139
6 40m39s 29105
7 180m41s 51912

Times are using -parallel=100 on a 12-core machine.

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package main
import (
"bufio"
"flag"
"fmt"
"io"
"log"
"os"
"runtime/pprof"
"strings"
"sync"
"time"
)
const alphabet = "abcdefghijklmnopqrstuvwxyz"
var (
wordsFile = flag.String("words_file", "/usr/share/dict/words", "File containing valid words")
numLetters = flag.Int("num_letters", 3, "Number of letters in resulting puzzles")
parallel = flag.Int("parallel", 3, "Number of goroutines to use to generate puzzles")
v = flag.Bool("v", false, "verbose logging")
cpuprofile = flag.String("cpuprofile", "", "write cpu profile to file")
)
func main() {
flag.Parse()
if *cpuprofile != "" {
f, err := os.Create(*cpuprofile)
if err != nil {
log.Fatal(err)
}
pprof.StartCPUProfile(f)
defer pprof.StopCPUProfile()
}
strings := make(chan string)
go genAllStrings(*numLetters, strings)
rotated := make(chan string)
go rotate(strings, rotated)
puzzles := make(chan puzzle)
// Consume puzzles and write files.
var wg2 sync.WaitGroup
wg2.Add(1)
go func() {
defer wg2.Done()
writePuzzles(puzzles)
}()
allWords := genAllWords()
// Consume rotated words and generate puzzles.
var wg sync.WaitGroup
for i := 0; i < *parallel; i++ {
wg.Add(1)
go func() {
defer wg.Done()
matchWords(allWords, rotated, puzzles)
}()
}
wg.Wait()
// When puzzle generators are done, close puzzles. This will cause
// writePuzzles to finish, and the program to exit.
close(puzzles)
wg2.Wait()
}
func genAllWords() []string {
f, err := os.Open(*wordsFile)
if err != nil {
log.Fatalf("Open(%q): %v", *wordsFile, err)
}
r := bufio.NewReader(f)
allWords := []string{}
for {
l, err := r.ReadBytes('\n')
if err == io.EOF {
break
}
if err != nil {
log.Fatalf("ReadBytes: %v", err)
}
w := string(l)
w = strings.TrimSpace(w)
// Words must be >5 letters.
if len(w) < 5 {
continue
}
// Words must be lowercase, no punctuation.
if !containsOnly(w, alphabet) {
continue
}
// Words must contain <=N unique letters.
if !hasAtMostLetters(w, *numLetters) {
continue
}
allWords = append(allWords, w)
}
f.Close()
fmt.Println("Matching", len(allWords), "words")
return allWords
}
func hasAtMostLetters(s string, n int) bool {
cs := map[rune]struct{}{}
for _, c := range s {
cs[c] = struct{}{}
if len(cs) > n {
return false
}
}
return true
}
// genAllStrings generates all unique strings of length n and sends them to
// out.
func genAllStrings(n int, out chan<- string) {
for _, c := range alphabet {
if n == 1 {
out <- string(c)
continue
}
ch := make(chan string, 1000)
go genAllStrings(n-1, ch)
for rest := range ch {
if rest[0] > byte(c) {
out <- string(c) + rest
}
}
}
close(out)
}
// rotate emits rotated versions of the string.
//
// If s is "abcdefg", out will be sent:
// - abcdefg
// - bcdefga
// - cdefgab
// - defgabc
// - efgabcd
// - fgabcde
// - gabcdef
func rotate(in <-chan string, out chan<- string) {
for s := range in {
for i := 0; i < len(s); i++ {
first, rest := s[:i], s[i:]
out <- rest + first
}
}
close(out)
}
type puzzle struct {
letters string
words []string
maxPts int
}
func containsOnly(s, target string) bool {
rs := map[rune]struct{}{}
for _, r := range target {
rs[r] = struct{}{}
}
for _, r := range s {
if _, found := rs[r]; !found {
return false
}
}
return true
}
// matchWords emits all words that match in (with spelling bee semantics).
func matchWords(allWords []string, in <-chan string, out chan<- puzzle) {
for s := range in {
runes := map[rune]struct{}{}
for _, c := range s {
runes[c] = struct{}{}
}
words := []string{}
for _, word := range allWords {
// Words must contain the first character.
if !strings.Contains(word, string(s[0])) {
continue
}
// Words must contain only letters in this set.
if containsOnly(word, s) {
words = append(words, word)
}
}
// This combination of letters doesn't produce enough answers.
if len(words) < 10 {
if *v {
fmt.Print("1")
}
continue
}
// Score the puzzle and ensure at least one answer uses all letters.
someContainsAll := false
maxPts := 0
for _, w := range words {
containsAll := true
for _, let := range s {
if !strings.ContainsRune(w, let) {
containsAll = false
}
}
if containsAll {
maxPts += 3
someContainsAll = true
} else {
maxPts += 1
}
}
if !someContainsAll {
if *v {
fmt.Print("2")
}
continue
}
out <- puzzle{
letters: s,
words: words,
maxPts: maxPts,
}
}
}
func writePuzzles(in <-chan puzzle) {
t := time.Tick(time.Second)
for {
select {
case p, ok := <-in:
if !ok {
return
}
fn := p.letters + ".txt"
f, err := os.Create(fn)
if err != nil {
log.Fatalf("Create(%q): %v", fn, err)
}
for _, w := range p.words {
fmt.Fprintln(f, w)
}
fmt.Fprintln(f, p.maxPts)
if *v {
fmt.Println("wrote", p.letters)
}
f.Close()
case <-t:
if *v {
fmt.Print("%")
}
}
}
}
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