FizBuz - shorter & sweeter

fizz_buzz.rb

# the classic FizzBuzz exercise, implemented with Ruby syntax
# at first, I wrote a script similar to the JavaScript exercise on Codeacademy.com
# Needless to say, the chain of if..else... statements just feels wrong.
# Below, with comments, is far superior code, modeled off http://www.rubyquiz.com/quiz126.html

# Start with an array of integers. We'll pass each integer individually to the block.

(1..100).each{ |i|

# Set an empty string as a default.
  x = ""

# insert the word "fizz" into the string if the present integer is divisible by 3.
# This action ("divisible by") is performed by the modulus. When we use the modulus,
# we're just seeing if there's a remainder when dividing by some number.
# No remainder means, by definition, the integer is divisible by the number.

  x += "fizz" if i%3==0

# Same thing as above, now we're just checking if the integer is divisible by 5.
  x += "buzz" if i%5==0

# Lastly, use a ternery operator. If the string remains empty for the tested integer,
# return the integer.
# otherwise, return the string.

  puts(x.empty? ? i : x);
}

# and we're done! Same logic as the Codeacademy.com FizzBuzz, but much sexier syntax!

# The full code, commented out so it doesn't print twice.

=begin
(1..100).each { |i|
  x = ''
  x += "fizz" if i%3==0
  x += "buzz" if i%5==0
  puts(x.empty? ? i : x);
}
=end