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@MaikKlein
Last active August 29, 2015 14:04
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# Define a daysBetweenDates procedure that would produce the
# correct output if there was a correct nextDay procedure.
#
# Note that this will NOT produce correct ouptuts yet, since
# our nextDay procedure assumes all months have 30 days
# (hence a year is 360 days, instead of 365).
#
def nextDay(year, month, day):
"""Simple version: assume every month has 30 days"""
if day < 30:
return year, month, day + 1
else:
if month == 12:
return year + 1, 1, 1
else:
return year, month + 1, 1
def daysBetweenDates(year1, month1, day1, year2, month2, day2):
days = 0
nd = day1
nm = month1
ny = year1
while !(nd == day2 && nm == month2 && ny == year2):
(ny, nm , nd) = nextDay(ny,nm,nd)
days += 1
return days
def test():
test_cases = [((2012,9,30,2013,10,30),30),
((2012,1,1,2013,1,1),360),
((2012,9,1,2012,9,4),3)]
for (args, answer) in test_cases:
result = daysBetweenDates(*args)
if result != answer:
print "Test with data:", args, "failed"
else:
print "Test case passed!"
test()
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