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@Mic92
Created December 14, 2011 08:17
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Berechnet alle Möglichkeiten für 7 a)
#!/usr/bin/ruby
class Node
attr_accessor :right, :middle, :left
attr_accessor :first_val, :second_val
def assign(first_val, second_val)
@first_val = first_val
@second_val= second_val
end
def neighbors(right, middle, left)
@right = right
@middle = middle
@left = left
end
def right_neighbors?
self != @right and
self != @middle and
self != @left
end
def ==(other_node)
(@first_val == other_node.first_val) or
(@first_val == other_node.second_val) or
(@second_val == other_node.first_val) or
(@second_val == other_node.second_val)
end
def to_s()
"[#{@first_val.to_s},#{@second_val.to_s}]"
end
end
# our map
# a0
#
# a1 a2 a3
# a4 a5
#
# a6 a7
# a8 a9
#
# dependencies
# a0: a1, a2, a3
# a1: a0, a4, a8
# a2: a0, a6, a7
# a3: a0, a5, a9
# a4: a1, a5, a7
# a5: a3, a4, a6
# a6: a2, a5, a8
# a7: a2, a4, a9
# a8: a1, a6, a9
# a9: a3, a7, a8
tuples = [ [1, 2], [1, 3], [1, 4], [1, 5],
[2, 3], [2, 4], [2, 5],
[3, 4], [3, 5],
[4, 5]]
neighbor_graph = [
[1, 2, 3],
[0, 4, 8],
[0, 6, 7],
[0, 5, 9],
[1, 5, 7],
[3, 4, 6],
[2, 5, 8],
[2, 4, 9],
[1, 6, 9],
[3, 7, 8],
]
nodes = Array.new(tuples.length) { Node.new }
nodes.each_index do |i|
r, m, l = neighbor_graph[i]
nodes[i].neighbors(nodes[r], nodes[m], nodes[l])
end
def dump_nodes(n, pos)
print(<<-eos
##{pos} solution
#{n[0]}
#{n[1]} #{n[2]} #{n[3]}
#{n[4]} #{n[5]}
#{n[6]} #{n[7]}
#{n[8]} #{n[9]}
eos
)
end
solutions = 0
tuples.permutation do |perm|
perm.each_index do |i|
nodes[i].assign(*perm[i])
end
right_node = true
nodes.each do |node|
if !node.right_neighbors? then
right_node = false
break
end
end
if right_node then
solutions = solutions + 1
dump_nodes(nodes, solutions)
end
end
print(solutions)
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