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@ReneSac
Created April 7, 2014 06:51
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proc sort*[A](t: var TCountTable[A]) =
## sorts the count table so that the entry with the highest counter comes
## first. This is destructive! You must not modify `t` afterwards!
## You can use the iterators `pairs`, `keys`, and `values` to iterate over
## `t` in the sorted order.
# we use shellsort here; fast enough and simple
var h = 1
while true:
h = 3 * h + 1
if h >= high(t.data): break
while true:
h = h div 3
for i in countup(h, high(t.data)):
var j = i
while t.data[j-h].val <= t.data[j].val:
swap(t.data[j], t.data[j-h])
j = j-h
if j < h: break
if h == 1: break
proc largest*[A](t: TCountTable[A]): tuple[key: A, val: int] =
## returns the (key,val)-pair with the largest `val`. Efficiency: O(n)
assert t.len > 0
var maxIdx = 0
for h in 1..high(t.data):
if t.data[maxIdx].val < t.data[h].val: maxIdx = h
result.key = t.data[maxIdx].key
result.val = t.data[maxIdx].val
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