iOS repl.it - Randomisation Challenge Solution

randomisation.swift

let alphabet = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]

//The number of letters in alphabet equals 26

var password = alphabet[Int.random(in: 0...25)] + alphabet[Int.random(in: 0...25)] + alphabet[Int.random(in: 0...25)] + alphabet[Int.random(in: 0...25)] + alphabet[Int.random(in: 0...25)] + alphabet[Int.random(in: 0...25)]  

print(password)

let alphabet = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"];

let a = alphabet.randomElement() ?? "";
let b = alphabet.randomElement() ?? "";
let c = alphabet.randomElement() ?? "";
let d = alphabet.randomElement() ?? "";
let e = alphabet.randomElement() ?? "";
let f = alphabet.randomElement() ?? "";
let password = a + b + c + d + e + f;

print(password);

Hi everyone! A lot of people here using more advanced techniques to solve the challenge. It's interesting to see all the ways it can be done. I'm glad I was also exactly like the official solution to show I'm on track!

let alphabet = [
"a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p",
"q", "r", "s", "t", "u", "v", "w", "x", "y", "z"
]

// The number of letters in alphabet equals 26

// a password of six random characters
var password: String = " "

for i in 1...6 {
password += alphabet.randomElement() ?? ""
}

print(password)

func exercise() {
let alphabet = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]

// Shuffle the alphabet and pick the first 6 letters
let shuffledAlphabet = alphabet.shuffled()
let password = shuffledAlphabet.prefix(6).joined()

print(password)

}

let alphabet = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]

//The number of letters in alphabet equals 26

let password = alphabet.randomElement()! + alphabet.randomElement()! + alphabet.randomElement()! + alphabet.randomElement()! + alphabet.randomElement()! + alphabet.randomElement()!

print(password)

The '!' on my code refers to force unwrapping optionals. Basically what optionals are saying is, "There is a value and it is [this value] or there isn't a value at all." If there wasn't a value at all, it would be 'nil'. if tried to run with randomElement alone the code would crash as will keep running and never find a solution.

Thank you for explaining this one. I am actually trying to use the alphabet.randomElement() but I was getting compiler error -- took too long to compile. Did not know you would need the '!'.

func exercise() {
let alphabet = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]

let password = (1...6).map { _ in alphabet.randomElement()! }.joined()

print(password)

}