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@TheMuellenator
Last active January 27, 2025 18:59
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iOS repl.it - Randomisation Challenge Solution
let alphabet = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
//The number of letters in alphabet equals 26
var password = alphabet[Int.random(in: 0...25)] + alphabet[Int.random(in: 0...25)] + alphabet[Int.random(in: 0...25)] + alphabet[Int.random(in: 0...25)] + alphabet[Int.random(in: 0...25)] + alphabet[Int.random(in: 0...25)]
print(password)
@micko4435
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func exercise() {
let alphabet = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]

// Shuffle the alphabet and pick the first 6 letters
let shuffledAlphabet = alphabet.shuffled()
let password = shuffledAlphabet.prefix(6).joined()

print(password)

}

@pbsi-00
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pbsi-00 commented Jan 27, 2025

let alphabet = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]

//The number of letters in alphabet equals 26

let password = alphabet.randomElement()! + alphabet.randomElement()! + alphabet.randomElement()! + alphabet.randomElement()! + alphabet.randomElement()! + alphabet.randomElement()!

print(password)

The '!' on my code refers to force unwrapping optionals. Basically what optionals are saying is, "There is a value and it is [this value] or there isn't a value at all." If there wasn't a value at all, it would be 'nil'. if tried to run with randomElement alone the code would crash as will keep running and never find a solution.

Thank you for explaining this one. I am actually trying to use the alphabet.randomElement() but I was getting compiler error -- took too long to compile. Did not know you would need the '!'.

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