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@Thomascountz
Last active March 5, 2023 12:50
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Perceptron in Python v.1
"""
MIT License
Copyright (c) 2018 Thomas Countz
Permission is hereby granted, free of charge, to any person obtaining a copy
of this software and associated documentation files (the "Software"), to deal
in the Software without restriction, including without limitation the rights
to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
copies of the Software, and to permit persons to whom the Software is
furnished to do so, subject to the following conditions:
The above copyright notice and this permission notice shall be included in all
copies or substantial portions of the Software.
THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
SOFTWARE.
"""
import numpy as np
class Perceptron(object):
def __init__(self, no_of_inputs, threshold=100, learning_rate=0.01):
self.threshold = threshold
self.learning_rate = learning_rate
self.weights = np.zeros(no_of_inputs + 1)
def predict(self, inputs):
summation = np.dot(inputs, self.weights[1:]) + self.weights[0]
if summation > 0:
activation = 1
else:
activation = 0
return activation
def train(self, training_inputs, labels):
for _ in range(self.threshold):
for inputs, label in zip(training_inputs, labels):
prediction = self.predict(inputs)
self.weights[1:] += self.learning_rate * (label - prediction) * inputs
self.weights[0] += self.learning_rate * (label - prediction)
@hoanW
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hoanW commented May 1, 2020

thank you for clearing that up.

@DebugHer
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DebugHer commented Dec 4, 2021

How can this be modified for OR?

@Thomascountz
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How can this be modified for OR?

To train for OR, you don't need to modify the code above. Instead, you update the training input such that the labels match the result of a logical OR and then train the model just as you would with AND.

import numpy as np
from perceptron import Perceptron

training_inputs = []
training_inputs.append(np.array([1, 1]))
training_inputs.append(np.array([1, 0]))
training_inputs.append(np.array([0, 1]))
training_inputs.append(np.array([0, 0]))

labels = np.array([1, 1, 1, 0])

perceptron = Perceptron(2)
perceptron.train(training_inputs, labels)

inputs = np.array([1, 1])
perceptron.predict(inputs) 
#=> 1

inputs = np.array([0, 1])
perceptron.predict(inputs) 
#=> 1

inputs = np.array([0, 0])
perceptron.predict(inputs) 
#=> 0

This demonstrates the flexibility of the perceptron/machine learning algorithms; they are adaptable general-purpose solvers!

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