solution-q2.txt

pi Customer.id, Customer.name ( Customer ⨝
	(
		pi id Customer - (
		rho id←custid (
			pi custid Account
		) )
	) )

tut1-relational-algebra.txt

-- this is an example

group: bankexample 


Customer = {
	id:number, name:string, city:string
	1, 'John', 'Lond'
	2, Mary, Edin
	3, Jeff, Lond
	4, Jane, Card
}

Account = {
	number:number, branch:string, custid:number, balance:number
	111, Lond, 1, 120
	222, Edin, 1, 62
	333, Lond, 3, 76
	444, Lond, 2, 200
}