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Redis offers a great deal of support for developing efficient caching mechanisms. It takes only a couple of minutes to implement a cache mechanism and get it working with any application. Follow along to learn 25 most common Redis Interview Questions and Answers for your next senior web developer interview.

Q1: What is Redis?

Topic: Redis
Difficulty: ⭐

Redis, which stands for Remote Dictionary Server, is a fast, open-source, in-memory key-value data store for use as a database, cache, message broker, and queue.

You can run atomic operations, like appending to a string; incrementing the value in a hash; pushing an element to a list; computing set intersection, union and difference; or getting the member with highest ranking in a sorted set.

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/* Check 

www.cryptowaves.app 

for Real-Time Crypto Market RSI Alerts! */

[
  {
    "id": 1,
    "name": "Bitcoin",

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{
  _id: "4c6b9456f61f000000007ba6"
  title: [
    { version: 1, value: "Hello world" },
    { version: 6, value: "Foo" }
  ],
  body: [
    { version: 1, value: "Is this thing on?" },
    { version: 2, value: "What should I write?" },
    { version: 6, value: "This is the new body" }

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{
   $lookup:
     {
       from: <collection to join>,
       localField: <field from the input documents>,
       foreignField: <field from the documents of the "from" collection>,
       as: <output array field>
     }
}

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{
  _id: "4c6b9456f61f000000007ba6"
  title: "Bar",
  body: "Is this thing on?",
  tags: [ "test", "trivial" ],
  comments: [
    { key: 1, author: "joe", body: "Something cool" },
    { key: 2, author: "xxx", body: "Spam", deleted: true },
    { key: 3, author: "jim", body: "Not bad at all" }
  ],

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double fibbonaci(int n){
    double prev=0d, next=1d, result=0d;
    for (int i = 0; i < n; i++) {
        result=prev+next;
        prev=next;
        next=result;
    }
    return result;
}

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function fibonacci(num, memo) {
  memo = memo || {};

  if (memo[num]) return memo[num];
  if (num <= 1) return 1;

  return memo[num] = fibonacci(num - 1, memo) + fibonacci(num - 2, memo);
}

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16/192 = 0.08333333...
208/16 = 13
...
11984/7408 = 1.61771058...
19392/11984 = 1.61815754...

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def FibonacciSearch(lys, val):
    fibM_minus_2 = 0
    fibM_minus_1 = 1
    fibM = fibM_minus_1 + fibM_minus_2
    while (fibM < len(lys)):
        fibM_minus_2 = fibM_minus_1
        fibM_minus_1 = fibM
        fibM = fibM_minus_1 + fibM_minus_2
    index = -1;
    while (fibM > 1):

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// |<--  p: F(n-2) - 1  -->|
// |<--- q --->|   |<- r ->|
// +---+---+---+
// |   | k |   | m
// +---+---+---+
//               ^