Max Consecutive Ones

MaxConsecutiveOnes.swift

/*
Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.
Note:

The input array will only contain 0 and 1.
The length of input array is a positive integer and will not exceed 10,000
*/

class Solution {
    
    func findMaxConsecutiveOnes(_ nums: [Int]) -> Int {
        
        var maxCount = 0
        var consecutive1s = 0
        for sub in stride(from: 0, to: nums.count, by: 1) {
            if nums[sub] == 1 {
                consecutive1s += 1
            } else {
                maxCount = (consecutive1s > maxCount) ? consecutive1s : maxCount
                consecutive1s = 0
            }
        }
        return (consecutive1s > maxCount) ? consecutive1s : maxCount
    }
}

print(Solution().findMaxConsecutiveOnes([1,1,0,1,1,1]))