Created
October 23, 2015 13:29
-
-
Save anirudhjayaraman/956e98680aeba8fd143a to your computer and use it in GitHub Desktop.
Counting the Number of Inversions In An Array
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
# load contents of text file into a list | |
# numList | |
NUMLIST_FILENAME = "IntegerArray.txt" | |
inFile = open(NUMLIST_FILENAME, 'r') | |
with inFile as f: | |
numList = [int(integers.strip()) for integers in f.readlines()] | |
count = 0 | |
def inversionsCount(x): | |
global count | |
midsection = len(x) / 2 | |
leftArray = x[:midsection] | |
rightArray = x[midsection:] | |
if len(x) > 1: | |
# Divid and conquer with recursive calls | |
# to left and right arrays similar to | |
# merge sort algorithm | |
inversionsCount(leftArray) | |
inversionsCount(rightArray) | |
# Merge sorted sub-arrays and keep | |
# count of split inversions | |
i, j = 0, 0 | |
a = leftArray; b = rightArray | |
for k in range(len(a) + len(b) + 1): | |
if a[i] <= b[j]: | |
x[k] = a[i] | |
i += 1 | |
if i == len(a) and j != len(b): | |
while j != len(b): | |
k +=1 | |
x[k] = b[j] | |
j += 1 | |
break | |
elif a[i] > b[j]: | |
x[k] = b[j] | |
count += (len(a) - i) | |
j += 1 | |
if j == len(b) and i != len(a): | |
while i != len(a): | |
k+= 1 | |
x[k] = a[i] | |
i += 1 | |
break | |
return x | |
# call function and output number of inversions | |
inversionsCount(numList) | |
print count |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment