Created
April 11, 2010 21:02
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import java.util.*; | |
public class Permute<E> | |
{ | |
/** | |
* Implementation of http://en.wikipedia.org/wiki/Permutation#Systematic_generation_of_all_permutations | |
Algorithm to effeciently generate permutations of a sequence | |
until all possiblities are exhausted | |
*/ | |
private int[] arrIdxs; | |
private ArrayList<E> arr; | |
public ArrayList<E> get_next() | |
{ | |
ArrayList<E> ret = new ArrayList<E>(); | |
for (int idx = 0 ; idx < arrIdxs.length;idx++) | |
ret.add(idx,arr.get(arrIdxs[idx])); //Permute integer based array indexes, which can be used to get permuted array in return | |
return ret; | |
} | |
public Permute(ArrayList<E> arr) | |
{ | |
this.arr = new ArrayList<E>(); | |
for (E each:arr) | |
this.arr.add(each); | |
arrIdxs = new int[arr.size()]; | |
for(int i = 0 ; i < arr.size();i++) //Set indexes lexicographically minimal value; | |
this.arrIdxs[i]= i; | |
} | |
public boolean next_permutation() | |
{ | |
int i,j,l; | |
for(j =arr.size() -2 ;j >=0 ; j--) //get maximum index j for which arr[j+1] > arr[j] | |
if (arrIdxs[j+1] > arrIdxs[j]) | |
break; | |
if (j == -1) //has reached it's lexicographic maximum value, No more permutations left | |
return false; | |
for(l = arr.size()-1;l > j ; l--) //get maximum index l for which arr[l] > arr[j] | |
if (arrIdxs[l] > arrIdxs[j]) | |
break; | |
int swap = arrIdxs[j]; //Swap arr[i],arr[j] | |
arrIdxs[j] = arrIdxs[l]; | |
arrIdxs[l] = swap; | |
for (i = j+1;i < arrIdxs.length;i++) //reverse array present after index : j+1 | |
{ | |
if (i > arrIdxs.length - i + j ) | |
break; | |
swap = arrIdxs[i]; | |
arrIdxs[i] = arrIdxs[arrIdxs.length - i + j]; | |
arrIdxs[arrIdxs.length - i + j] = swap; | |
} | |
return true; | |
} | |
public static void main(String[] args) | |
{ | |
/** | |
* Test Run | |
*/ | |
ArrayList<String> test_arr = new ArrayList<String>(); | |
test_arr.add("ab");test_arr.add("b");test_arr.add("c");test_arr.add("d"); | |
Permute<String> test = new Permute<String>(test_arr); | |
while (true) | |
{ | |
System.out.println(test.get_next().toString()); | |
if (!test.next_permutation()) | |
break; | |
} | |
} | |
} |
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def getNextPermute(arr): | |
""" | |
Implementation of http://en.wikipedia.org/wiki/Permutation#Systematic_generation_of_all_permutations | |
Algorithm to effeciently generate permutations of a sequence | |
returns a generator type object, which for each call return next possible permutation | |
until all possiblities are exhausted | |
""" | |
arr.sort() | |
yield arr[:] | |
while True: | |
for j in xrange(len(arr)-2,-1,-1): #find larget a[j]<a[j+1] | |
if arr[j+1] > arr[j]: | |
break | |
else: | |
return | |
for l in xrange(len(arr)-1,j,-1): #find larget a[j]<a[l] | |
if arr[l] > arr[j]: | |
break | |
arr[j],arr[l] = arr[l],arr[j] #swap a[j],a[l] | |
arr[j+1:] = arr[j+1:][::-1] #reverse array present after the index (j+1)th | |
yield arr[:] | |
if __name__=="__main__": | |
assert len(list(getNextPermute([5,1,2,3,4]))) == 120 | |
for each in getNextPermute(["a","b","c"]): | |
print ','.join(each) | |
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