athaeryn

let app = Express.App.make()

let taskPool = TaskPool.make()

// How can I just get the Pause.output back out of this, and avoid
// doing extra work to check if the output is from the wrong Task?
app.get(."/pause", (. _req, res) => {
  taskPool.run(Pause({howLongMs: 4200}))
  ->Promise.thenResolve(result => {
    switch result {

athaeryn

// ----
// Sass (v3.3.8)
// Compass (v1.0.0.alpha.19)
// ----

/*
 * inspired by:
 * http://www.smashingmagazine.com/2014/06/12/sassy-z-index-management-for-complex-layouts/
 */
$z: (

athaeryn

import React, { PureComponent } from "react";
import { StyleSheet } from "react-native";
import ReglView from "./ReglView";
import mat4 from "gl-mat4";
import bunny from "bunny";

export default class Bunny extends PureComponent {
  drawCommand = regl => {
    return regl({
      vert: `

athaeryn

How I have NeoVim set up for ReasonML Development

Install neovim python package:

$ pip2 install neovim
$ pip3 install neovim

---

athaeryn

install aviglitch gem

gem install aviglitch

run mo.sh

./mo.sh input.gif

athaeryn

#!/bin/sh

if ! hash chrome-cli 2>/dev/null; then
  echo "Couldn't find chrome-cli. Ensure it's installed and on your PATH."
  exit 1
fi

DIRNAME="/tmp/codpen+$(date '+%s')"
INDEX="$DIRNAME/index.html"
RELOAD="$DIRNAME/reload"

athaeryn

autocmd! BufWritePost * silent! !chrome-cli reload

athaeryn

const fs = require('fs')

const words = fs.readFileSync('/usr/share/dict/words')
  .toString()
  .toLowerCase()
  .split('\n')

const alphabet = 'abcdefghijklmnopqrstuvwxyz'.split('')

let lookup =

athaeryn

Keybase proof

I hereby claim:

• I am athaeryn on github.
• I am athaeryn (https://keybase.io/athaeryn) on keybase.
• I have a public key whose fingerprint is 11B8 5003 D377 5BCD 1667 C508 9065 E768 2896 8C89

To claim this, I am signing this object:

athaeryn

console.log(
  (Array(100) + "")
    .split(",")
    .map(function(s, i) {
      return !!(++i % 3) || (s += "Fizz"),
             !!(  i % 5) || (s += "Buzz"),
                       s || i;
    })
    .join("\n")
);