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Goofing with Elixir Lang
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## | |
## Define an .ex file that is compiled with elixirc | |
## | |
defmodule Hack do | |
def reverse_list([h|t], acc // []) do | |
Hack.reverse_list(t, List.concat([h], acc)) | |
end | |
def reverse_list([], acc) do | |
acc | |
end | |
def sum([h|t], acc) do | |
sum(t, h + acc) | |
end | |
def sum([], acc) do | |
acc | |
end | |
end | |
## | |
## compile: elixirc reverse-list.ex | |
## start iex in same dir as the .beam | |
## | |
## iex(1)> Hack.reverse_list [1,2,3] | |
## [3, 2, 1] | |
## | |
## | |
## Now define a .exs (script file) | |
## | |
defmodule Hack do | |
def reverse_list([h|t], acc) do | |
Hack.reverse_list(t, List.concat([h], acc)) | |
end | |
def reverse_list([], acc) do | |
acc | |
end | |
def sum([h|t], acc) do | |
sum(t, h + acc) | |
end | |
def sum([], acc) do | |
acc | |
end | |
end | |
x = Hack.reverse_list [1,2,3], [] | |
IO.puts "#{is_list x}" | |
IO.puts "The length of x is #{length x}" | |
IO.puts "#{x}" | |
theSum = Enum.reduce(x, 0, fn(x, acc) -> x + acc end) | |
IO.puts "The sum of the invisible list is #{theSum}" | |
y = Hack.sum [1,2,3], 0 | |
IO.puts "The result is #{y}" | |
## | |
## Save this and run it using: | |
## elixir reverse-list.exs | |
## | |
## the output of script is: | |
## >> true | |
## >> The length of x is 3 | |
## >> | |
## >> The sum of the invisible list is 6 | |
## >> The result is 6 | |
## The question is... why am i not seeing the list in stdout yet i am seeing that it's a list, it has length 3 and sum of 6 | |
## confused! |
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