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@cTxplorer
Created May 29, 2017 04:20
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Snackdown - Is it a snake
//contest link: https://www.codechef.com/SNCKPA17/problems/ISSNAKE
//Author: Pratik Gadhiya
#include<iostream>
using namespace std;
char arr[502][2]; // Original array
int tot; // total number of '#' in an array
int n;
bool traverse(int x, int y){
int vert = 0; // to check whether we have traversed vertically in that column
int trav = 0; // trav -> total number of '#' traversed
int i, j;
for ( i=x, j=y; i<n; ){
if ( arr[i][j] == '.' ) break; // Initial condition
++trav; // Increment trav if '#'
if ( !vert && arr[i][1-j]=='#' ){ // check if the other cell in column is '#'
vert = 1; // signifies that we have traversed vertically
j = 1-j; // move to other cell in same column
}
else{ // else move to right
vert = 0; // we haven't traversed vertically in new column
++i;
}
}
if ( trav == tot ) // if all '#' are traversed
return true;
return false;
}
int main(){
int t, i;
cin >> t;
while ( t-- ){
cin >> n;
tot = 0;
// scanning row 0
for ( i=0; i<n; ++i ){
cin >> arr[i][0];
if ( arr[i][0]=='#' ) ++tot;
}
// scanning row 1
for ( i=0; i<n; ++i ){
cin >> arr[i][1];
if ( arr[i][1]=='#' )
++tot;
}
// Finding the leftmost column with atleast one '#'
for ( i=0; i<n; ++i )
if ( arr[i][0]=='#' || arr[i][1] == '#' )
break;
/* calling traverse to traverse the array
traverse(i,0) -> start traversal from (i, 0)
Don't worry, if arr[i][0] = '.', it would be false */
if ( i<n && (traverse(i, 0) || traverse(i,1)) )
cout << "yes\n";
else
cout << "no\n";
}
return 0;
}
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