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[CC150][2.5] You have two numbers represented by a linked list, where each node contains a single digit The digits are stored in reverse order, such that the 1’s digit is at the head of the list Write a function that adds the two numbers and returns the sum as a linked list. EXAMPLE Input: (3 -> 1 -> 5) + (5 -> 9 -> 2) Output: 8 -> 0 -> 8
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import java.util.LinkedList; | |
import java.util.ListIterator; | |
import java.util.Random; | |
public class add { | |
public static LinkedList<Integer> addList(LinkedList<Integer> a, | |
LinkedList<Integer> b) { | |
LinkedList<Integer> result = new LinkedList<Integer>(); | |
ListIterator<Integer> iterA = a.listIterator(); | |
ListIterator<Integer> iterB = b.listIterator(); | |
int m = 0; | |
int addValue; | |
while (iterA.hasNext() || iterB.hasNext()) { | |
addValue = (iterA.hasNext() ? iterA.next() : 0) + | |
(iterB.hasNext() ? iterB.next() : 0) + m; | |
result.add(addValue % 10); //add signal digit to result | |
m = (addValue - addValue % 10) / 10; // update tens digit for next loop | |
} | |
return result; | |
} | |
public static void main (String[] args) { | |
Random rd = new Random(); | |
LinkedList<Integer> testA = new LinkedList<Integer>(); | |
LinkedList<Integer> testB = new LinkedList<Integer>(); | |
System.out.println("*************test***************"); | |
for (int i = 0; i < 5; i++) | |
testA.add(rd.nextInt(10)); | |
System.out.println(testA.toString()); | |
for (int i = 0; i < 7; i++) | |
testB.add(rd.nextInt(10)); | |
System.out.println(testB.toString()); | |
LinkedList<Integer> result = add.addList(testA, testB); | |
System.out.println(result.toString()+"\n"); | |
System.out.println("*************test***************"); | |
testA.clear(); | |
testB.clear(); | |
result.clear(); | |
for (int i = 0; i < 8; i++) | |
testA.add(rd.nextInt(10)); | |
System.out.println(testA.toString()); | |
for (int i = 0; i < 5; i++) | |
testB.add(rd.nextInt(10)); | |
System.out.println(testB.toString()); | |
result = add.addList(testA, testB); | |
System.out.println(result.toString()+"\n"); | |
System.out.println("*************test***************"); | |
testA.clear(); | |
testB.clear(); | |
result.clear(); | |
for (int i = 0; i < 5; i++) | |
testA.add(rd.nextInt(10)); | |
System.out.println(testA.toString()); | |
System.out.println(testB.toString()); | |
result = add.addList(testA, testB); | |
System.out.println(result.toString()+"\n"); | |
} | |
} |
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