AoC2020_10.jl

## Input
D = parse.(Int, readlines("./10.txt"));
diffs = [D[1]; diff(sort(D)); 3]

## Part 1
p1 = sum(diffs.==1)*sum(diffs.==3);

## Part 2
v = [1;0;0];
for d = diffs
    global v;
    if d == 1
        v = [1 1 1;1 0 0;0 1 0]*v;
    elseif d == 2
        v = [1 1 0;0 0 0;1 0 0]*v;
    else
        v = [1 0 0;0 0 0;0 0 0]*v;
    end
end
p2 = v[1];

## Output
println((p1, p2));

Wow! You're sorting twice, though. :)

Wow! You're sorting twice, though. :)

You can never be too sure lol. Whoops, missed that when compressing up the messy code I originally ran for the solution, thanks!