Created
April 13, 2014 15:49
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My submissions to KTH Challenge 2014
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#include <stdio.h> | |
int main() { | |
int D, n1, n2; | |
scanf("%d", &D); | |
for (n1 = 0; n1 < D; n1++) | |
for (n2 = 0; n2 < n1; n2++) | |
if ((n1 + n2) * (n1 - n2) == D) { | |
printf("%d %d\n", n2, n1); | |
return 0; | |
} | |
printf("impossible\n"); | |
return 0; | |
} |
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#!/usr/bin/python3 | |
import heapq | |
N, M = [int(x) for x in input().split()] | |
links = dict() | |
for i in range(M): | |
u, v, w = [int(x) for x in input().split()] | |
if u not in links: | |
links[u] = set() | |
links[u].add((v, w)) | |
s, t = [int(x) for x in input().split()] | |
best = dict() | |
paths = list() | |
q = list() | |
heapq.heappush(q, (0, s, set([s]))) | |
while len(q) > 0: | |
d, u, path = heapq.heappop(q) | |
if u == t: | |
paths.append(path) | |
elif u in links: | |
for v, w in links[u]: | |
if v not in best or d + w <= best[v]: | |
best[v] = d + w | |
heapq.heappush(q, (d + w, v, path.union([v]))) | |
common = paths[0].intersection(*paths[1:]) | |
common = [str(x) for x in common] | |
print(" ".join(common)) | |
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#!/usr/bin/python3 | |
i = input() | |
try: | |
h, d = i.split() | |
except ValueError: | |
h = i | |
d = "" | |
n = 1 | |
for p in d: | |
n = n * 2 | |
if p == 'R': | |
n = n + 1 | |
n = 2 ** (int(h) + 1) - n | |
print(n) |
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#include <stdio.h> | |
int main() { | |
double D, lo = 0.0, hi = 1.0, templo, temphi; | |
int N, c, i, sum = 0; | |
scanf("%lf %d", &D, &N); | |
for (i = 1; i <= N; i++) { | |
scanf("%d", &c); | |
sum = sum + c; | |
templo = sum - i*D; | |
temphi = templo + 1; | |
if (lo < templo) | |
lo = templo; | |
if (hi > temphi) | |
hi = temphi; | |
if (lo > hi) { | |
printf("impossible\n"); | |
return 0; | |
} | |
} | |
printf("possible\n"); | |
return 0; | |
} |
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