fast way to remove large number of redis keys by pattern

fast-remove-redis-keys.py

# to remove all keys matching a pattern in redis
# we could use the recommended way: redis-cli --scan --pattern 'abc:*' | xargs redis-cli del
# but this can be very slow if you have lots of data (like 8G redis cluster)
# we can use the following script to remove keys (considerably faster)

import time
import logging
from rediscluster import StrictRedisCluster

logger = logging.getLogger(__name__)
client = StrictRedisCluster(startup_nodes=hosts, password=password,
                                    skip_full_coverage_check=True)

pattern = "abc:*"
start_time = time.time()
item_count = 0
batch_size = 100000
keys = []

logger.info("Start scanning keys...")

for k in client.scan_iter(pattern, count=batch_size):
    keys.append(k)
    if len(keys) >= batch_size:
        item_count += len(keys)
        logger.info("batch delete to {} ...".format(item_count))

        client.delete(*keys)
        keys = []

if len(keys) > 0:
    item_count += len(keys)
    logger.info("batch delete to {}".format(item_count))

    client.delete(*keys)

end_time = time.time()

logger.info("deleted {0} keys in {1:0.3f} ms.".format(item_count, (end_time - start_time) / 1000.0))

Thanks for this gitst. This is much faster than not using count=batch_size. Saves me a lot of the time.

@andsens I don't think this works with Cluster Mode enabled right? I was getting CROSSSLOT errors

@DaveLanday hm, no that would fail. A multikey (500 keys in this case) operation, if I understand cluster mode correctly (never used it), has to operate on the same hashing slot.