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| <!DOCTYPE html> | |
| <html> | |
| <head> | |
| <meta name="description" content="Call any function just once within a period of time"> | |
| <meta charset="utf-8"> | |
| <meta name="viewport" content="width=device-width"> | |
| <title>JS Bin</title> | |
| </head> | |
| <body> | |
| <input type="button" value="Call function 3 times" onclick="onClick()"> |
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| //Добавить событие longtap, которое возникает при длительном (1с) нажатии на элемент | |
| //Переопределяется метод addEventListener у прототипа Element, таким образом, что: | |
| //Если новый метод вызывается для события touchstart, то callback метода декорируется: | |
| //- у элемента проставляется флаг isTouched | |
| //- перед вызовом исходного callback запускается timeout, по окончании которого проверится флаг isTouched и вызовется запуск события longtap | |
| //Если новый метод вызывается для события touchend, то callback метода декорируется: | |
| //- снимается флаг isTouched | |
| const longtapEvent = new Event("longtap"); |
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| var ARR_MIN_LENGTH = 5; | |
| var ARR_MAX_LENGTH = 10; | |
| var arr = getArbitraryArray(); | |
| //var arr = [1, 10, 3, 2, 7, 3, 8, 9]; | |
| console.log(arr, find(arr, 10)); | |
| //arr - массив натуральных чисел. | |
| function find(arr, target) { |
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| "use strict"; | |
| //An equilibrium index of a sequence is an index into the sequence such that the sum of elements at lower indices is equal to the sum of elements at higher indices. | |
| //two loops | |
| function eq(arr) { | |
| if (arr.length === 0) { | |
| return -1; | |
| } | |
| for (var i = 0; i < arr.length; i++) { |
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| "use strict"; | |
| var m = 3; | |
| var n = 4; | |
| function next(seq) { | |
| //find i, seq[i] < m, seq[i + 1] = seq[n] = m | |
| var i = n - 1; | |
| console.log(seq); | |
| while (i >= 0 && seq[i] == m) { |
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| <div class="container"> | |
| <div class="inner"> | |
| <div class="text"> | |
| Lorem ipsum dolor sit amet. | |
| </div> | |
| </div> | |
| </div> |
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| //Способ с перебором массива | |
| function isPalindrome(s){ | |
| s = s.toLowerCase().replace(/[^а-яё]/g, ""); | |
| for (var i = 0; i < s.length / 2; i++){ | |
| var b = s[i]; | |
| var e = s[s.length - 1 - i]; | |
| if (b !== e) | |
| { | |
| return false; |
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| //взять случайное число из пространства длины массива | |
| //переставить элемент с этим индексом и последний элемент | |
| //уменьшить индекс длины на единицу | |
| //повторить все это в цикле пока не дойдем до первого элемента | |
| function getNewArray(arr){ | |
| var res = arr.slice(); | |
| var max = res.length - 1; | |
| var i, e; | |
| while(max > 0){ | |
| i = getRandomIntInclusive(0, max); |
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| //Find longest sequence of zeros in binary representation of an integer. | |
| function solution(n) { | |
| var str = toBinaryString(n).replace(/0+$/, ""); | |
| var arr = str.split("1").filter(function(e) { return e.length > 0; }); | |
| if (arr.length === 0){ | |
| return 0; | |
| } | |
| arr.sort(function(a, b){ return b.length - a.length; }); | |
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| /* | |
| A string S consisting of N characters is considered to be properly nested if any of the following conditions is true: | |
| S is empty; | |
| S has the form "(U)" or "[U]" or "{U}" where U is a properly nested string; | |
| S has the form "VW" where V and W are properly nested strings. | |
| For example, the string "{[()()]}" is properly nested but "([)()]" is not. | |
| */ | |
| var rb = { |
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