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My solution for UVA 10258
#include <iostream>
#include <cstring>
#include <vector>
#include <string>
#include <sstream>
#include <algorithm>
using namespace std;
typedef vector<int> vi;
int solved[101][10], penalty[101][10];
inline bool mySort(int i, int j) {
int isolve=0, ip=0, jsolve=0, jp=0;
for(int a=0; a<10; a++) if(solved[i][a]) {
ip += penalty[i][a];
for(int a=0; a<10; a++) if(solved[j][a]) {
jp += penalty[j][a];
if(isolve > jsolve) return true;
else if(isolve < jsolve) return false;
else {
if(ip < jp) return true;
else if(ip > jp) return false;
else return i < j;
int t, id, p, n;
char L;
vi participants;
int main() {
cin >> n;
string s;
getline(cin, s);
getline(cin, s);
while(n--) {
memset(solved, 0, sizeof(int)*101*10);
memset(penalty, 0, sizeof(int)*101*10);
while(getline(cin, s), s.size()>0) {
stringstream ss(s);
ss >> id >> p >> t >> L;
if(L=='I' && !solved[id][p]) penalty[id][p]+=20;
else if(L=='C') {
if(!solved[id][p]) penalty[id][p]+=t;
solved[id][p] = 1;
if(find(participants.begin(), participants.end(), id) == participants.end())
sort(participants.begin(), participants.end(), mySort);
for(int k : participants) {
int s=0, p=0;
for(int i=0; i<10; i++)
if(solved[k][i]) {
printf("%d %d %d\n", k, s, p);
if(n > 0) printf("\n");
return 0;
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