Created
February 18, 2016 22:53
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Depth first search code for pair programming with the Recurse Center
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import networkx as nx | |
def dfs(node, graph, start): | |
leaves = [n for n, d in graph.out_degree().items() if d == 0] | |
root = [n for n, d in graph.in_degree().items() if d == 0] | |
if start == "": | |
start = root[0] | |
if start == node: | |
return node | |
if start in leaves: | |
if start in root: | |
return node + ' is not in this tree' | |
parent = graph.predecessors(start)[0] | |
graph.remove_edge(parent, start) | |
return dfs(node, graph, parent) | |
for child in graph.successors(start): | |
return dfs(node, graph, child) | |
""" | |
The rest of this code is for testing. | |
When running the test function, I am expecting either the node in the | |
first parameter of dfs to return if the node is in the graph created in | |
create_graph, or to return a statement that the node is not in the tree | |
if it is not in the graph. | |
Family tree is a non-binary tree. | |
""" | |
def create_graph(tree): | |
graph = nx.DiGraph() | |
for node in tree.keys(): | |
for value in tree[node]: | |
graph.add_edge(node, value) | |
return graph | |
def test(): | |
family_tree = {'root': ['child1', 'child2'], | |
'child1': ['gc1', 'gc2'], | |
'child2': ['gc3'], | |
'gc3': ['ggc1', 'ggc2', 'ggc3']} | |
graph = create_graph(family_tree) | |
print(dfs('ggc2', graph, start="")) | |
if __name__ == '__main__': | |
test() |
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