ethanal

print([(i%3==0)*"Fizz"+(i%5==0)*"Buzz" or i for i in range(100)])

ethanal

import cStringIO as StringIO
from random import randint
import sys
from PIL import Image
import wand.image


input_filepath = sys.argv[1]

img = Image.open(input_filepath)

ethanal

def baseconv(v1, a1, a2):
    if v1 == a1[0]: return a2[0]
    v2 = ""
    n1 = {c: i for i, c in enumerate(a1)}
    b1 = len(a1)
    b2 = len(a2)
    d1 = 0
    
    for i, c in enumerate(v1):
        d1 += n1[c] * pow(b1, len(v1) - i - 1)

ethanal

def invert(b):
    return "".join(str(int(not int(c))) for c in b)


def encode_float(f):
    b = bin(abs(int(round(f * 1e5))))[2:]
    b = ("0" * (32 - len(b))) + b

    if f < 0:
        b = invert(b)

ethanal

ethanal

Keybase proof

I hereby claim:

• I am ethanal on github.
• I am ethanal (https://keybase.io/ethanal) on keybase.
• I have a public key whose fingerprint is 178B 38FA 151F C237 625D 55B0 944F E97D 33AB DB60

To claim this, I am signing this object:

ethanal

import functools
from time import time
from .text_styles import *


class ProfileItem(object):

    def __init__(self, name, elapsed, stats):
        self.name = name
        self.elapsed = elapsed

ethanal

import os
import sys
import platform


def _style(code):
    def wrapper(string):
        if os.isatty(sys.stdout.fileno()) and platform.system() != "Windows":
            return "\033[{:02}m{}\033[00m".format(code, string)
        return string

ethanal

\documentclass[11pt]{article}

\usepackage[letterpaper]{geometry}
\geometry{top=0.5in, bottom=0.5in, left=0.7in, right=0.7in}

\usepackage{courier}
\usepackage{listings}

\usepackage{fancyhdr}
\pagestyle{fancy}

ethanal

import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.Arrays;
import java.util.HashMap;

import org.apache.poi.xssf.usermodel.XSSFWorkbook;
import org.apache.poi.ss.usermodel.Sheet;
import org.apache.poi.ss.usermodel.Workbook;