Convertierung of dtb to yml files

Convertierungs script

#!/usr/bin/env python3

import fdt
import getopt
import os
import sys
import yaml


def main(argv):
    inputdir = ''
    outputdir = ''
    filenames = []

    try:
        opts, args = getopt.getopt(argv,"hi:o:",["input-dir=","output-dir="])
    except getopt.GetoptError:
        print('device-info.py -i <inputdir> -o <outputdir>')
        sys.exit(2)

    for opt, arg in opts:
        if opt == '-h':
            print('device-info.py -i <inputdir> -o <outputdir>')
            sys.exit()
        elif opt in ("-i", "--input-dir"):
            inputdir = arg
        elif opt in ("-o", "--output-dir"):
            outputdir = arg

    folder = os.fsencode(inputdir)

    for file in os.listdir(folder):
        filename = os.fsdecode(file)
        if filename.endswith( ('.dtb') ):
            filenames.append(os.path.splitext(filename)[0])

    filenames.sort()

    for file in filenames:
        info = {}
        yml_file = file + ".yml"
        yml_file = os.path.join(os.path.abspath(outputdir), yml_file)
        dtb_file = file + ".dtb"
        dtb_file = os.path.join(os.path.abspath(inputdir), dtb_file)
        with open(dtb_file, "rb") as f:
            print("Parse dtb: " + dtb_file)
            dtb_data = f.read()
            dtb = fdt.parse_dtb(dtb_data)
            info['soc'] = dtb.get_property("compatible")[0]
            info['model'] = dtb.get_property("model")[0]
        with open(yml_file, 'w') as f:
            print("Write yml: " + yml_file)
            yaml.dump(info, f)

if __name__ == "__main__":
    main(sys.argv[1:])

Pipfile for pipenv

[[source]]
name = "pypi"
url = "https://pypi.org/simple"
verify_ssl = true

[dev-packages]

[packages]
fdt = "*"
pyyaml = "*"

[requires]
python_version = "3.7"