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Divide integer num much equally with bash
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#!/bin/bash | |
ceiling () { | |
local divide="$1";shift | |
local by="$1" | |
printf "%s\\n" $(( ( divide + by - 1 ) / by )) | |
} | |
equalized_partition_nums () { | |
local number="$1";shift | |
local count="$1" | |
local upper lower upper_count lower_count | |
upper="$(ceiling "$number" "$count")" | |
lower=$(( upper - 1 )) | |
lower_count=$(( upper * count - number )) | |
upper_count=$(( count - lower_count )) | |
# echo "upper_count=$upper_count upper=$upper lower_count=$lower_count lower=$lower " | |
eval "printf '${upper} %.0s' {1..$upper_count}" | |
(( lower_count > 0 )) && eval "printf '${lower} %.0s' {1..$lower_count}" | |
} | |
equalized_partition_nums 100 10 | awk 4 | |
equalized_partition_nums 100 6 | awk 4 | |
equalized_partition_nums 9 4 | awk 4 | |
IFS=" " read -r -a arr <<< "$(equalized_partition_nums 9 4)" | |
seq 0 "${#arr[@]}" | while read -r i ;do | |
printf '%s=%s\n' "$i" "${arr[i]}" | |
don |
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