Makefile

CLIBS = ""

foo:
	@echo "CLIBS is '${CLIBS}'"

test.sh

#!/bin/bash
set -e

# echo command & execute
foo() {
  echo "$*"
  eval "$*"
}

# echo command & execute without escape.
foo2() {
  echo "$*"
  "$@"
}

libs="-L/usr/local/lib -L/lib/x86_64-linux-gnu/"

# Just want to add `foo` function but quote in parameter will disapper. Need escape quote like \"\"
# ただ foo 関数を頭につけてあげたいが、パラメーターの "" が消えてしまうので \"\" でエスケープが必要

# CLIBS is '-L/usr/local/lib -L/lib/x86_64-linux-gnu/'
echo "* echo ..."
make foo CLIBS="$libs"

# 🚀 GOOD.
# make foo CLIBS="-L/usr/local/lib -L/lib/x86_64-linux-gnu/"
# CLIBS is '-L/usr/local/lib -L/lib/x86_64-linux-gnu/'
echo "* run \\ ..."
foo make foo CLIBS=\"$libs\"

# 😢 BAD.
# make foo CLIBS=-L/usr/local/lib -L/lib/x86_64-linux-gnu/
# make: invalid option -- '/'
# Usage: make [options] [target] ...
# foo make foo CLIBS="$libs" # require escape "libs" -> \"$libs\"

# 🤔 SOSO. missing quote from `echo` message.
# make foo CLIBS=-L/usr/local/lib -L/lib/x86_64-linux-gnu/
# CLIBS is '-L/usr/local/lib -L/lib/x86_64-linux-gnu/'
echo "* run ..."
foo2 make foo CLIBS="$libs"