Python 3에서 함수의 위치 인자와 주석문 http://blog.hannal.com/2015/03/positioning_argument_and_annotations_for_python3_function/

checking_argument_type_with_annotation_on_python3

# works on Python 3

def check_argument_type(func):
    def wrapper(*args):
        if (
            not hasattr(func, '__annotations__') or
            len(func.__annotations__) == 0
        ):
            return func(*args)

        try:
            check_index = \
                func.__annotations__['args'].index(Ellipsis)
        except ValueError:
            check_index = \
                len(func.__annotations__['args']) - 1

        for _i, _v in enumerate(args[:check_index]):
            _arg_type = func.__annotations__['args'][_i]

            if isinstance(_v, _arg_type):
                continue

            raise TypeError(
                "The type of '{}' does not match '{}' type".format(
                    _v, _arg_type.__name__
                )
            )
        return func(*args)
    return wrapper

@check_argument_type
def hello_func(*args: (int, int, ...)):
    print(*args)

hello_func(1, 2, '3', 'a')

positional_argument_on_python3

# works on Python 3

def args2_func(arg1, *, arg2, arg3):
    print(arg1, arg2, arg3)

args2_func('hello', 'world', '!')
args2_func('!', arg3='hello', arg2='world')
args2_func('world', arg3='!', arg2='hello')
args2_func('hello', '!', arg3='world')

def kwargs_func(*, arg1, arg2, arg3):
    print(arg1, arg2, arg3)

kwargs_func(arg1='hello', arg2='world', arg3='!')