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@happyWinner
Created July 11, 2014 16:59
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/**
* Write an algorithm to find the 'next' node (i.e., in-order successor) of a given node in a binary search tree.
* You may assume that each node has a link to its parent.
*
* Time Complexity: O(h)
* Space Complexity: O(1)
*/
public class Question4_6 {
public TreeNode getSuccessor(TreeNode node) {
if (node == null) {
return null;
}
if (node.right != null) {
TreeNode retNode = node.right;
while (retNode.left != null) {
retNode = retNode.left;
}
return retNode;
}
TreeNode prevNode = node;
TreeNode retNode = node.parent;
while (retNode != null && retNode.right == prevNode){
prevNode = retNode;
retNode = retNode.parent;
}
return retNode;
}
public static void main(String[] args) {
Question4_6 question4_6 = new Question4_6();
TreeNode root = new TreeNode(4, null);
root.left = new TreeNode(2, root);
root.right = new TreeNode(6, root);
root.left.left = new TreeNode(1, root.left);
root.left.right = new TreeNode(3, root.left);
root.right.left = new TreeNode(5, root.right);
root.right.right = new TreeNode(7, root.right);
System.out.println(question4_6.getSuccessor(root.left.left).value);
System.out.println(question4_6.getSuccessor(root.left).value);
System.out.println(question4_6.getSuccessor(root.left.right).value);
System.out.println(question4_6.getSuccessor(root).value);
System.out.println(question4_6.getSuccessor(root.right.left).value);
System.out.println(question4_6.getSuccessor(root.right).value);
System.out.println(question4_6.getSuccessor(root.right.right) == null ? "null" : "not null");
}
}
class TreeNode {
int value;
TreeNode left;
TreeNode right;
TreeNode parent;
public TreeNode() {
this(0, null, null, null);
}
public TreeNode(int value, TreeNode parent) {
this(value, null, null, parent);
}
public TreeNode(int value, TreeNode left, TreeNode right, TreeNode parent) {
this.value = value;
this.left = left;
this.right = right;
this.parent = parent;
}
}
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