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@hsjoihs
Created September 30, 2019 14:20
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\frac{2}{ab}\frac{d^3}{d\theta^3} S_{true} = -2ab\left(1+m^2\right) \left( \frac{ 2\sin \theta\cos\theta}{L}-\frac{ 2abm \sin^3 \theta}{L^2} \right) + \frac{dm}{d\theta} \left(-\frac{4abm \sin^2 \theta}{L}+\cos\theta\right)-m\sin\theta -\cos \theta
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