Workaround for ExpatError when talking to bugzilla servers

gistfile1.py

import bugzilla
import xmlrpclib
import types
import unicodedata

class FilterParser(object):
    """
    Filtering object that strips control characters before actually parsing
    """
    def __init__(self, parser):
        self.parser = parser

    def __getattr__(self, attr):
        """Pass through to bound methods of self.parser"""
        return getattr(self.parser, attr)

    def feed(self, data):
        """
        Overridden feed(data) method which strips control characters before
        passing to the underlying parser.feed(data) method.

        See xmlrpclib.ExpatParser.feed
        """
        data = ''.join(c for c in data.decode('utf-8', 'replace')
                       if c == '\n'
                       or unicodedata.category(c) != 'Cc').encode('utf-8')
        self.parser.feed(data)


bg = bugzilla.Bugzilla(url=xmlrpc_url, cookiefile=None)

# Override getparser method of transport
# TODO: upgrade to python-bugzilla 0.9.0 for self.bg._transport
transport = bg._proxy._ServerProxy__transport
transportcls = transport.__class__
orig_getparser = transport.getparser

def getparser(self):
    """
    Creates a parser. See xmlrpclib.Transport.getparser.
    """
    parser, unmarshaller = orig_getparser()
    parser = FilterParser(parser)
    return parser, unmarshaller

transport.getparser = types.MethodType(getparser, transport,
                                       transportcls)