Find the palindrome larger than given number

next_palindrome.py

import math 

def find_next(n):
    try:
        n = int(n)
    except:
        return n
    
    if n < 10:
        return n
    
    n += 1
    
    length = len(str(n))
    
    for i in range(1, ((length)/2)+1):
        # extract first and last i digits of n
        fd = str(n)[0:i]
        ld = str(n)[-i:][::-1]
        
        # increase n by 10^i-1(1, 10, 100 ...) in each loop
        # and check if first and last i digits are equal
        # if n = 2133, first increate by 1 until last digit is 2
        # then increate by 10 untill first 2 and last 2 digits are equal
        while fd != ld:
            n += int(math.pow(10, i-1))
            fd = str(n)[0:i]
            ld = str(n)[-i:][::-1]
        
    return n

print find_next(1111111112)