100個のフィボナッチ数のリストを計算せよ（但しできるところまで）

FibonacciGen.swift

#!/usr/bin/env xcrun swift

func FibonacciGen(inout fibtbl:[Int]) {
    var f0 = 0
    var f1 = 1
    var fib = 0
    fibtbl[0] = 0
    fibtbl[1] = 1
    for var i = 2; i < 100; i++ {
        fib = f0 &+ f1
        if fib < 0 {
            println("\(i+1): Over floow")
            break
        }
        fibtbl[i] = fib
        f0 = f1
        f1 = fib
    }
    return
}

var fibtbl:[Int] = Array(count: 100, repeatedValue: 0)

FibonacciGen( &fibtbl )
for var i = 0; i < fibtbl.count; ++i {
    println("\(i)\t\(fibtbl[i])")
}