jackhftang

def permutations(lis):
    N = len(lis)
    i = 0
    c = [*range(0, max(2,N+1))]
    while True:
        yield lis
        i = 1
        while c[i] == 0:
            c[i] = i
            i += 1

jackhftang

import asyncdispatch
import deques
import options
import httpclient
import strformat

export httpclient # for AsyncResponse

#[
  Wrapping AsyncHttpClient for pooling and timeout, also see

jackhftang

you are a zoo keeper, You wanna keep animals to be healthy (not overweight) so you apply a diet plan.
Problem:
An animal has intial weight S at the start, For every day, you can choose to lose weight (a[i]) or have food (b[i]) or , but you have to make sure every day animal doesnt exceed T (target weight)
for N days plan, how many possbile combinations can have
condition
・1 ≦ N ≦ 35
・1 ≦ Ai, Bi ≦ 1,000,000,000 (1 ≦ i ≦ N)
・(sum of A_i) < S ≦ T ≦ 1,000,000,000
sample in
2 10 20

jackhftang

proc fletcher16*(arr: openArray[uint8]): uint16 = 
  var 
    c1: int = 0
    c2: int = 0
  for d in arr:
    c1 += d.int
    c2 += c1
  result = (((c2 mod 255) shl 8) + (c1 mod 255)).uint16
  

jackhftang

<?php

/**
 * LDAP PHP Change Password Webpage
 *
 * Copyright (C) 2010 Matt Rude <http://mattrude.com>
 * Copyright (C) 2019 Jack Tang <me@jackhftang.com>
 *
 * This program is free software: you can redistribute it and/or modify
 * it under the terms of the GNU General Public License as published by

jackhftang

package util 

import (
	"time"
)

<?php
$className = "StringMap";
$arr = [
	"Bool" => "bool",

jackhftang

There is a colony of 8 cells arranged in a straight line where each day every cell competes with its adjacent cells(neighbour). Each day, for each cell, if its neighbours are both active or both inactive, the cell becomes inactive the next day,. otherwise itbecomes active the next day.

Assumptions: The two cells on the ends have single adjacent cell, so the other adjacent cell can be assumsed to be always inactive. Even after updating the cell state. consider its pervious state for updating the state of other cells. Update the cell informationof allcells simultaneously.

Write a fuction cellCompete which takes takes one 8 element array of integers cells representing the current state of 8 cells and one integer days representing te number of days to simulate. An integer value of 1 represents an active cell and value of 0 represents an inactive cell.

jackhftang

#define FOR(i, n) for (i = 0;i < n;++i)
#define sv static void

typedef unsigned char u8;
typedef unsigned long u32;
typedef unsigned long long u64;
typedef long long i64;
typedef i64 gf[16]; // 1024-bit = 128 bytes

static const gf _121665 = {0xDB41, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0};

jackhftang

const cluster = require('cluster')
const N = 8

if(cluster.isMaster){
  let workers = {}
  let globals = []
  for(let i=0; i<N; i++) workers[i] = cluster.fork({id: i});
  cluster.on('message', (worker, {message, timestamp, to}) => {
    globals.push({timestamp, message})
    globals.sort(function(x,y){

jackhftang

const cluster = require('cluster');
const minions = ['alpha', 'beta'];
const tHeartBeat = 1000
const tCheck = 1000
const tTimeout = 3000

if (cluster.isMaster) {
  for (let id of minions) cluster.fork({id});

  let lastHeartbeat = {}