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@jamesshah
Last active Feb 26, 2021
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TicTacToe Game implemented in python3
#Implementation of Two Player Tic-Tac-Toe game in Python.
''' We will make the board using dictionary
in which keys will be the location(i.e : top-left,mid-right,etc.)
and initialliy it's values will be empty space and then after every move
we will change the value according to player's choice of move. '''
theBoard = {'7': ' ' , '8': ' ' , '9': ' ' ,
'4': ' ' , '5': ' ' , '6': ' ' ,
'1': ' ' , '2': ' ' , '3': ' ' }
board_keys = []
for key in theBoard:
board_keys.append(key)
''' We will have to print the updated board after every move in the game and
thus we will make a function in which we'll define the printBoard function
so that we can easily print the board everytime by calling this function. '''
def printBoard(board):
print(board['7'] + '|' + board['8'] + '|' + board['9'])
print('-+-+-')
print(board['4'] + '|' + board['5'] + '|' + board['6'])
print('-+-+-')
print(board['1'] + '|' + board['2'] + '|' + board['3'])
# Now we'll write the main function which has all the gameplay functionality.
def game():
turn = 'X'
count = 0
for i in range(10):
printBoard(theBoard)
print("It's your turn," + turn + ".Move to which place?")
move = input()
if theBoard[move] == ' ':
theBoard[move] = turn
count += 1
else:
print("That place is already filled.\nMove to which place?")
continue
# Now we will check if player X or O has won,for every move after 5 moves.
if count >= 5:
if theBoard['7'] == theBoard['8'] == theBoard['9'] != ' ': # across the top
printBoard(theBoard)
print("\nGame Over.\n")
print(" **** " +turn + " won. ****")
break
elif theBoard['4'] == theBoard['5'] == theBoard['6'] != ' ': # across the middle
printBoard(theBoard)
print("\nGame Over.\n")
print(" **** " +turn + " won. ****")
break
elif theBoard['1'] == theBoard['2'] == theBoard['3'] != ' ': # across the bottom
printBoard(theBoard)
print("\nGame Over.\n")
print(" **** " +turn + " won. ****")
break
elif theBoard['1'] == theBoard['4'] == theBoard['7'] != ' ': # down the left side
printBoard(theBoard)
print("\nGame Over.\n")
print(" **** " +turn + " won. ****")
break
elif theBoard['2'] == theBoard['5'] == theBoard['8'] != ' ': # down the middle
printBoard(theBoard)
print("\nGame Over.\n")
print(" **** " +turn + " won. ****")
break
elif theBoard['3'] == theBoard['6'] == theBoard['9'] != ' ': # down the right side
printBoard(theBoard)
print("\nGame Over.\n")
print(" **** " +turn + " won. ****")
break
elif theBoard['7'] == theBoard['5'] == theBoard['3'] != ' ': # diagonal
printBoard(theBoard)
print("\nGame Over.\n")
print(" **** " +turn + " won. ****")
break
elif theBoard['1'] == theBoard['5'] == theBoard['9'] != ' ': # diagonal
printBoard(theBoard)
print("\nGame Over.\n")
print(" **** " +turn + " won. ****")
break
# If neither X nor O wins and the board is full, we'll declare the result as 'tie'.
if count == 9:
print("\nGame Over.\n")
print("It's a Tie!!")
# Now we have to change the player after every move.
if turn =='X':
turn = 'O'
else:
turn = 'X'
# Now we will ask if player wants to restart the game or not.
restart = input("Do want to play Again?(y/n)")
if restart == "y" or restart == "Y":
for key in board_keys:
theBoard[key] = " "
game()
if __name__ == "__main__":
game()
@code-simple
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code-simple commented Aug 11, 2020

can i use it for my project ?

@jamesshah
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Author

jamesshah commented Aug 12, 2020

@code-simple Sure. Go ahead.

@blacks1
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blacks1 commented Dec 15, 2020

Cool

@Tony04031234
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Tony04031234 commented Feb 26, 2021

Too cool !!!

@blacks1
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blacks1 commented Feb 26, 2021

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