Created
January 23, 2017 19:08
-
-
Save jianminchen/7a2778829ccb31210d8850e581a99048 to your computer and use it in GitHub Desktop.
Leetcode 56 - Merge intervals - using C# SortedSet to sort intervals, define Comparator - Julia learned a few things through the code.
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
using System; | |
using System.Collections.Generic; | |
using System.Diagnostics; | |
using System.Linq; | |
using System.Text; | |
using System.Threading.Tasks; | |
namespace MergeIntervals | |
{ | |
class Program | |
{ | |
/** | |
* Definition for an interval. | |
*/ | |
public class Interval | |
{ | |
public int start; | |
public int end; | |
public Interval() { start = 0; end = 0; } | |
public Interval(int s, int e) { start = s; end = e; } | |
} | |
/* | |
* IntervalComparer is to compare the interval start value, but if | |
* the two have the same value, then compare end value. | |
* | |
*/ | |
public class IntervalComparer : IComparer<Interval> | |
{ | |
public int Compare(Interval leftHandSide, Interval rightHandSide) | |
{ | |
if (leftHandSide.start == rightHandSide.start) | |
{ | |
return leftHandSide.end.CompareTo(rightHandSide.end); | |
} | |
return leftHandSide.start.CompareTo(rightHandSide.start); | |
} | |
} | |
static void Main(string[] args) | |
{ | |
RunSampleTestcase1(); | |
RunSampleTestcase2(); | |
} | |
/* | |
* Test case: | |
* help to test intervals should be sorted first before merging. | |
* [1,4], [0,4] should not be [1,4] | |
*/ | |
public static void RunSampleTestcase1() | |
{ | |
IList<Interval> intervals = new List<Interval>(); | |
intervals.Add(new Interval(1, 4)); | |
intervals.Add(new Interval(0, 4)); | |
IList<Interval> nonoverlapped = Merge(intervals); | |
Debug.Assert(nonoverlapped[0].start == 0 && nonoverlapped[0].end == 4); | |
} | |
/* | |
* Test case: | |
* help to test that edge case is handled properly . | |
* [1,4] should be [1,4], not [] | |
* In other words, there is one interval in the input, the result should be itself. | |
* For loop | |
*/ | |
public static void RunSampleTestcase2() | |
{ | |
IList<Interval> intervals = new List<Interval>(); | |
intervals.Add(new Interval(1, 4)); | |
IList<Interval> nonoverlapped = Merge(intervals); | |
Debug.Assert(nonoverlapped.Count == 1); | |
} | |
/* | |
* Merge all overlapping intervals | |
* Output: all intervals are non-overlapped. | |
* | |
* Sort intervals using binary search tree, O(nlogn) algorithm. | |
* Go over intervals from start smallest to bigger ones, check two intervals, denoting | |
* current, next. | |
* | |
* If two intervals do not have overlapped, then do nothing. Otherwise, | |
* set current interval to maximum of two intervals' end, and remove | |
* next interval. | |
* | |
* source code from code review post: | |
* http://codereview.stackexchange.com/a/153418/123986 | |
*/ | |
public static IList<Interval> Merge(IList<Interval> intervals) | |
{ | |
var sortedIntervals = new SortedSet<Interval>(intervals, new IntervalComparer()); | |
for (int i = 0; i < sortedIntervals.Count - 1; i++) | |
{ | |
Interval current = sortedIntervals.ElementAt(i); | |
Interval next = sortedIntervals.ElementAt(i + 1); | |
// two intervals are overlapped | |
if (next.start - current.end < 1) | |
{ | |
// set current interval's end, and then remove next interval | |
current.end = Math.Max(current.end, next.end); | |
sortedIntervals.Remove(next); | |
i--; // go back to old index, continue | |
} | |
} | |
return sortedIntervals.ToList(); | |
} | |
} | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment